<span>f(x) = 2x + 1
y = 2x + 1
x = 2y + 1
x - 1 = 2y
0.5x - 0.5 =
f^-1(x)</span>
Answer:
a) , , b) , ,
Step-by-step explanation:
a) The values of the output for steady-state operation are:
b) The formula for linearization is:
The first derivative of the formula evaluated at x = 1 is:
The linearized model is:
The output at x = 2 is presented below:
Linearized model offers reasonable approximations for small intervals.
Answer:
See explanation below.
Step-by-step explanation:
No.
The distance between 19 and 15 is 4. Both numbers are positive, 4 units apart.
The distance between -19 and -15 is also 4. Both numbers are negative, 4 units apart.
When you find the distance from 19 to -15, keep in mind that one number is positive, 19, and one number is negative, -15. The two numbers are on different side of zero on the number line.
Start at -15. -15 is 15 units to the left of zero. To get to 0, you need to go 15 units right. Now you need to go from 0 to 19. That is another 19 units right. Add 15 + 19 to get 34.
The distance from 19 to -15 on a number line is not 4. It is 34.
The length of a football field should be measured in yards
Answer:
Step-by-step explanation:
The given relation between length and width can be used to write an expression for area. The equation setting that equal to the given area can be solved to find the shed dimensions.
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<h3>Given relation</h3>
Let x represent the width of the shed. Then the length is (2x+3), and the area is ...
A = LW
20 = (2x+3)(x) . . . . . area of the shed
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<h3>Solution</h3>
Completing the square gives ...
2x² +3x +1.125 = 21.125 . . . . . . add 2(9/16) to both sides
2(x +0.75)² = 21.125 . . . . . . . write as a square
x +0.75 = √10.5625 . . . . . divide by 2, take the square root
x = -0.75 +3.25 = 2.50 . . . . . subtract 0.75, keep the positive solution
The width of the shed is 2.5 feet; the length is 2(2.5)+3 = 8 feet.