Solve the equation 3(x +4.5) = 36

Ja'Kiree has a bunch of quarters and nickels in her piggy bank totaling $8.75. If Ja'Kiree has 26 quarters, how many nickels doe

evablogger [386]

Start off by stating your facts. You have a maximum of $8.75. We know that each quarter is 25 cents so we multiply 25x26 equaling 650. Yet we need a decimal so it would be $6.50. Each nickel is worth 5 cents so then you would minus $8.75 and $6.50 getting us to $2.25. Now divide it by 5 cents and you should get 45 nickels. You can also do this by stating that 10 nickels is 50 cents and go until you get 45

6 0

3 years ago

3.30 Survey response rate. Pew Research reported in 2012 that the typical response rate to their surveys is only 9%. If for a pa

Artist 52 [7]

Answer:

0% probability that at least 1,500 will agree to respond

Step-by-step explanation:

I am going to use the binomial approximation to the normal to solve this question.

Binomial probability distribution

Probability of exactly x sucesses on n repeated trials, with p probability.

Can be approximated to a normal distribution, using the expected value and the standard deviation.

The expected value of the binomial distribution is:

$E(X) = np$

The standard deviation of the binomial distribution is:

$\sqrt{V(X)} = \sqrt{np(1-p)}$

Normal probability distribution

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

When we are approximating a binomial distribution to a normal one, we have that $\mu = E(X)$ , $\sigma = \sqrt{V(X)}$ .

In this problem, we have that:

$n = 15000, p = 0.09$

So

$\mu = E(X) = np = 15000*0.09 = 1350$

$\sigma = \sqrt{V(X)} = \sqrt{np(1-p)} = \sqrt{15000*0.09*0.91} = 35.05$

What is the probability that at least 1,500 will agree to respond

This is 1 subtracted by the pvalue of Z when X = 1500-1 = 1499. So

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{1499 - 1350}{35.05}$

$Z = 4.25$

$Z = 4.25$ has a pvalue of 1.

1 - 1 = 0

0% probability that at least 1,500 will agree to respond

6 0

3 years ago

Some please help answer this step by step

egoroff_w [7]

It might be wrong but this is how i solved it: i used the elimination method to solve this and got x is 3-4y and y is all real numbers
first multiply the top equation by 5 and then you get:
5x+20y=15
-5x-20x=-15
since all the numbers are canceled out it is all real numbers.

then for x since you can’t substitute the y back in i just did:
x=3-4y
i just moved over the 4y

and to prove it you can say you substituted several points and they all worked
hope this helped let me know if you have any questions

8 0

3 years ago

What is the greatest common factor of 96x^2 and 88x

nevsk [136]

Answer:

GCF = 8x

Step-by-step explanation:

Find the GCF of the constants:

96 and 88 are both divisible by 8 which is the GCF of the constants.

The GCF of the variables is x, as you cannot divide x by anything more than x.

The total GCF is 8x.

5 0

3 years ago

Solve 2^(6x-12)=(32)^(3x+12) for x.

sp2606 [1]

Answer:The answer is x/52

Step-by-step explanation:

7 0

2 years ago

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