A company is studying the number of monthly absences among its 125 employees. The following probability distribution shows the l
ikelihood that people were absent 0, 1, 2, 3, 4, or 5 days last month.
Picture
col1# of days absent 0 1 2 3 4 5
col2Probability 0.60 0.20 0.12 0.04 0.04 0
What is the variance of the number of days absent?
a. 1.1616
b. 55.52
c. 5.00
d. 1.41
1 answer:
Answer:
a. 1.1616
Step-by-step explanation:
Variance is given by:
Where "xi" is each individual number of absences, and "pi" are their respective probability. The mean number of absences is:
Applying the given data, the variance is:
The variance of the number of days absent is 1.1616 days
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