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3 years ago

When your classmates began their hike, they

Mathematics

2 answers:

Ede4ka [16]3 years ago

8 0

Answer:

% increase = 200%

Step-by-step explanation:

deff fn [24]3 years ago

6 0

Answer:

Step-by-step explanation:

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A test to detect an infection gives a positive result 98% of the time if a person is infected. It is 97% accurate for people who

Rama09 [41]

If the test gives a positive result for an infected person 98% of the time, that means that 2% of the time, it gives a negative result for an infected person, which would be a false negative.

If the test is 97% accurate for non-infected people, that means that it gives a negative result 97% of the time. So a positive result will be given 3% of the time for non-infected people, which is a false positive.

6 0

2 years ago

How do I solve (7-6i)(-8+3i)?

Alekssandra [29.7K]

I = {2.666666667, 1.166666667

6 0

2 years ago

Read 2 more answers

The school that Lisa goes to is selling tickets to the annual talent show. On the first day of ticket sales the school sold 4 se

kakasveta [241]

Let:
x = cost of senior citizen ticket
y = cost of student ticket

4x + 5y = 102
7x + 5y = 126

4x + 5y = 102
4x = 102 - 5y
x = (102 - 5y)/4
x = 102/4 - 5y/4

7x + 5y = 126
7(102/4 - 5y/4) + 5y = 126
(714/4 - 35y/4) + 5y = 126
-35y/4 + 5y = 126 - 714/4

note:
-35y/4 = -8.75y
714/4 = 178.5

-8.75y + 5y = 126 - 178.5
-3.75y = -52.5
y = -52.5/-3.75
y = 14

x = 102/4 - 5y/4
x = 102/4 - 5(14)/4
x = 8

x = cost of senior citizen ticket = $8/ea
y = cost of student ticket = $14/ea

6 0

2 years ago

500 cats were chosen. 52% of the cats liked to sleep inside the house. Fish was the favorite dish of 25% of those cats, while 62

Alex777 [14]

You would need to take 500 * .52 = 260 next take 260 * .25 to find how many cats like fish which equals 65, the probability that it likes fish and it sleeps inside can be found by taking .52 * .25 = .13 so there would be a 13% chance of picking a cat that sleeps indoors and likes fish, 435 cats dont like fish found by taking 500-65=435 and finally to find how many cats sleep outside take 500-260=240 then take 240 * .625 = 150 then 240-150 = 90 so 90 cats like to sleep outside and like fish thats it!=) Hope this helps!

3 0

2 years ago

Read 2 more answers

A publisher reports that 344% of their readers own a particular make of car. A marketing executive wants to test the claim that

inysia [295]

Answer:

No, there is not enough evidence at the 0.02 level to support the executive's claim.

Step-by-step explanation:

We are given that a publisher reports that 34% of their readers own a particular make of car. A random sample of 220 found that 30% of the readers owned a particular make of car.

And, a marketing executive wants to test the claim that the percentage is actually different from the reported percentage, i.e;

Null Hypothesis, $H_0$ : p = 0.34 {means that the percentage of readers who own a particular make of car is same as reported 34%}

Alternate Hypothesis, $H_1$ : p $\neq$ 0.34 {means that the percentage of readers who own a particular make of car is different from the reported 34%}

The test statistics we will use here is;

T.S. = $\frac{\hat p -p}{\sqrt{\frac{\hat p(1- \hat p)}{n} } }$ ~ N(0,1)

where, p = actual % of readers who own a particular make of car = 0.34

$\hat p$ = percentage of readers who own a particular make of car in a

sample of 220 = 0.30

n = sample size = 220

So, Test statistics = $\frac{0.30 -0.34}{\sqrt{\frac{0.30(1- 0.30)}{220} } }$

= -1.30

Now, at 0.02 significance level, the z table gives critical value of -2.3263 to 2.3263. Since our test statistics lie in the range of critical values which means it doesn't lie in the rejection region, so we have insufficient evidence to reject null hypothesis.

Therefore, we conclude that the actual percentage of readers who own a particular make of car is same as reported percentage and the executive's claim that it is different is not supported.

3 0

2 years ago