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galben [10]
2 years ago
11

Add: 8 yd 1 ft + 11 yo 2 ft

Mathematics
1 answer:
PSYCHO15rus [73]2 years ago
4 0

Answer:

19 yards 3 ft

60 ft

20 yards

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Solve using substitution method x-y=11;3x+10y=-6<br> explain please
Tatiana [17]
Ok so for starters you want to choose an equation and solve for a variable.
So, I am going to choose x from the first equation.
Add y to both sides and you get x=11+y
Next, substitute 11+y for x in the other equation so you get...
2(11+y) +10y=-6
Next distribute the 2 throug the 11 and the y
22+2y+10y=-6
12y=-28
y=-28/12
reduce this fraction to make this easier.
y=-7/3
Now plug in why to either of the equations to find x
x-(-7/3)=11
x+7/3=11
x=11-(7/3)
x=(33/3)-(7/3)
x=26/3
so x = 26/3 and y = -7/3
you can also check to see if this is correct by substituting each of these values into the equations.
6 0
2 years ago
Rewrite the equation 2x + 4y + 2 = 3y + 5 in general form. A. 2x + 7y + 7 = 0 B. 2x + y – 3 = 0 C. 2x + y = 3 D. y = –2x + 3
kvasek [131]
2x + 4y + 2 = 3y + 5
2x + 4y - 3y + 2 - 5 = 0
2x + y - 3 = 0
7 0
3 years ago
Read 2 more answers
Write 9.68 x 104 in standard form?
-Dominant- [34]

Answer:

1006.72

Step-by-step explanation:

Multiply 9.68 by 104

7 0
3 years ago
Read 2 more answers
21/50 of the seats for the football game have been sold. This is equal to what decimal?
valentinak56 [21]
First make the fraction over 100

21/50(2/2) = 42/100

42/100 = 0.42 

0.42 is your answer

hope this helps
6 0
2 years ago
A model car travels around a circular track with radius 5 feet. Let Z denote the distance between the model car and a fixed poin
Eddi Din [679]

Answer:

\frac{dZ}{dt}= \frac{40}{\sqrt{545} } , so the model car is moving away from the fixed point at a rate of approximately 1.7 feet per second.

Step-by-step explanation:

The functions x and y satisfy (x−20)^2+y^2=25 and differentiating gives 2(x−20)dx/dt+2y dy/dt=0. Substituting the three known values and solving for dy/dt yields dy/dt=−32. Since Z=x^2+y^2−−−−−−√, dZ/dt=(2x ^ dx/dt+2y^dy/dt) / 2x2+y2√. Substituting Since Substituting for x, y,\frac{dx}{dt} , and \frac{dy}{dt} gives \frac{dZ}{dt}= \frac{40}{\sqrt{545} } ,

5 0
3 years ago
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