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Setler79 [48]
3 years ago
10

1. Which equation is equivalent to the equation 6x + 9 = 12?

Mathematics
1 answer:
tresset_1 [31]3 years ago
5 0

Answer:

B) 2x+3=4

Step-by-step explanation:

6x+9=12

6x=12-9

6x=3

x=3/6

x=1/2

---------------

Because 2x+3=4, 2x=4-3, 2x=1, x=1/2.

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10 fish are in a tank, 3 fish drown, how many fish are left?
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10. Fish don't drown (; nice try tho
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Sally has completed 1/3 of her shift; Jerry has completed 5/6 of his shift; David has finished 1/2 of his shift; Mona has 7/8 of
Step2247 [10]
Sally = 1/3
Jerry = 5/6
David = 1/2
Mona = 1 - 7/8 = 1/8

So, the biggest fraction among them is 5/6.

Jerry has completed the most work time. 
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3 years ago
Multiplying Vertically:
Ad libitum [116K]

Answer:

6. Find the product for both sets of polynomials below by multiplying vertically. (4 points: 2 points for each product)

A)

4x^4 - 4x^3 - 16x^2 + 16x

B)

4x^4 - 4x^3 - 16x^2 + 16x

7. Are the two products the same when you multiply them vertically? (1 point)

Yes, the two products are the same when you multiply them.

Making a Decision:

8. Who was right, Emily or Zach? Are the products the same with the three different methods of multiplication? (1 point)

Emily was right, the products are the same with all three different methods of multiplication.

9. Which of these three methods is your preferred method for multiplying polynomials? Why? (1 point)

I prefer the table method because it is easier to understand what is going on, know where and what to do, and it is nicely and neatly laid out in front of me.

4 0
2 years ago
In a certain Algebra 2 class of 28 students, 11 of them play basketball and 13 of them play baseball. There are 11 students who
mina [271]
80 + 28 - 13 = 95 + 11 = 106
3 0
3 years ago
Is the answer a, b, c, or d.
ale4655 [162]
The correct answer is d.

We have the following system of linear equations:

(I) 4x+7y=-14
(II) 8x+5y=8

Let's use the elimination method, then let's multiply the equation (1) \times(-2) and subtracting (I) and (II):

(I) -2(4x+7y)=-2(-14)
∴ -8x-14y=28

(I) -8x-14y=28
(II) 8x+5y=8
____________________
(III)  -9y=36

∴  y=-4

We can find the value of x by substituting y either in (I) or (II). Thus, from (I):

4x+7(-4)=-14
∴ 4x-28=-14
∴ 4x=14
∴ x=\frac{14}{4}
∴ \boxed{x=\frac{7}{2}}

Let's substitute the values of x and y into (I) and (2)

(I) 4(\frac{7}{2})+7(-4)=14-28=-14
(II) 8(\frac{7}{2})+5(-4)=28-20=8

Finally the answer is:

\boxed{x=\frac{7}{2} \rightarrow x= 3 \frac{1}{2}}

4 0
3 years ago
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