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3 years ago

Write an integer (positive or negative whole number) to represent each description.

Mathematics

1 answer:

vazorg [7]3 years ago

6 0

Answer:

Football player= -5

Number line= -23

Step-by-step explanation:

Loss means negative

Left on a number line is subtraction

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Factor: x^2 + 11xy - 26y^2

irina1246 [14]

Hello.

(x + 2y) • (x - 13y) Step by step solution :Step 1 :Equation at the end of step 1 : ((x2) - 11xy) - (2•13y2) Step 2 :Trying to factor a multi variable polynomial :

2.1 Factoring x2 - 11xy - 26y2

Try to factor this multi-variable trinomial using trial and error

Found a factorization : (x + 2y)•(x - 13y)

Final result : (x + 2y) • (x - 13y)

Have a nice day

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3 years ago

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Mekela earned $65.25 for 9 hours of work. This week she earned $101.50 for 14 hours. Which equation represents the relationship

cestrela7 [59]

Y = 7.25x

Where x = hours.

You can get this by dividing the amount by the amount of hours in each pair.

6 0

3 years ago

Stacey and Michele both babysit in the evening.staceys hours rate is $10 for one child plus $2per additional child Michael hourl

lara31 [8.8K]

They have two children...
8 + 3c = 10 + 2c
c = 2

7 0

3 years ago

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A car is moving with a velocity (3.0 m/s) x̂ + (1.0 m/s) ŷ and 3.0 seconds later its velocity is (6.0 m/s) x̂ - (3.0 m/s) ŷ. Wha

Mars2501 [29]

Here we know that the initial velocity of the car is given by:

$V_i=(3.0\hat x+1.0\hat y)m/s$

And the final velocity of the car is given by:

$V_f=(6.0\hat x-3.0\hat y)m/s$

It took 3 seconds to attain the final velocity, so we have $t=3 s$

Therefore, the acceleration can be obtained by:

$V_f-V_i=a\times t$

$a=\frac{V_f-V_i}{t}$

Plugging the values of the initial, final velocity and the time, we get:

$a= \frac{(6\hat x-3\hat y)-(3 \hat x+1 \hat y)}{3} =\frac{6\hat x-3 \hat y -3 \hat x-1 \hat y}{3} =\frac{3 \hat x-4 \hat y}{3}$

So the acceleration of the car is given by:

$a=\frac{3 \hat x}{3} -\frac{4 \hat y}{3} =1 \hat x- \frac{4}{3} \hat y$

Now we need to find the direction of the average acceleration of the car:

$\theta=tan^{-1} \frac{y}{x}$

Here, x and y are the coefficients of the 'x' and 'y' components of the vector:

$\theta=tan^{-1}(\frac{-\frac{4}{3} }{1} )=tan^{-1}(\frac{-4}{3}) =-53.13^\circ$

Therefore, the direction of the average acceleration of the car is $-53.13^\circ$ .

8 0

4 years ago

Lines / and m are parallel.

Black_prince [1.1K]

Answer:l and m?

Step-by-step explanation:

might I b correct...

4 0

3 years ago