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Tema [17]
3 years ago
12

For a data set with a mean of 150 and a standard Deviation of 15, use chebyshev theorem to find the interval of which 75% of the

data will fall.
Mathematics
1 answer:
svp [43]3 years ago
7 0
The Chebychev's theorem states that for any numerical data set,
1.) at least \frac{3}{4} of the data lie within two standard deviations of the mean;
2.) <span> at least </span><span><span>\frac{8}{9} of the data lie within three standard deviations of the mean</span>;
3.) at least </span><span><span>1-\frac{1}{k^2} of the data lie within k standard deviations of the mean,</span> where k is any positive whole number that is greater than 1.</span>

Thus, given a data set with a mean of 150 and a standard Deviation of 15, 75% of the data represent \frac{3}{4} of the data, and according to Chebychev's theorem, <span>at least \frac{3}{4} of the data lie within two standard deviations of the mean.

Thus, 75% of the data will fall within the interval
150\pm2(15)=150\pm30=(150-30,\ 150+30)=(120,\ 180).

Therefore, 75% of the data will fall within the interval 120 to 180.</span>
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<em>The large sample size 'n' =  199.6569≅ 200</em>

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<u><em>Step(i)</em></u>:-

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<em>   (S.D ) σ =  $5,478,384.55</em>

Given estimate of this average salary for all baseball players for 2015

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<em>Given Margin of error of error is  =  $497,000 </em>

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<em>The critical value Z₀.₂₀ = 1.282  </em>

<u><em>Step(ii):</em></u><em>-</em>

<em>Margin of error of error is  determined by</em>

<em>           </em>M.E = \frac{Z_{0.20} S.D}{\sqrt{n} }<em></em>

<em>          </em>497,000 = \frac{1.282 X 5,478,384.55}{\sqrt{n} }<em></em>

Cross multiplication , we get

 \sqrt{n}  = \frac{1.282 X 5,478,384.55}{497,000 }

On calculation , we get

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<em>Squaring on both sides, we get</em>

n = 199.6569

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<em>The large sample size 'n' =  199.6569≅ 200</em>

<em>    </em>

<em></em>

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