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3 years ago

What was the median number of the text message that she sent 7, 4, 5, 13,

Mathematics

1 answer:

yarga [219]3 years ago

8 0

7+4+5+13=29 and you divide that by 4 and your answer is 7.25

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Is 3x+2x=3 a function

trasher [3.6K]

Yes this is a function

8 0

3 years ago

5x+20y=4<br> x=-4y+1<br><br> Solve for x/y

Andrews [41]

Hi there!

Looks like a lot of work is going on here.

Let's start by solving this equation for the x.

$5x + 20y = 4$

Step 1) Add -20y to both sides.

$5x + 20y + - 20y = 4 - 20y 5x = -20y + 4$

Step 2) Divide both sides by 5.

$\frac{5x}{5} = \frac{-20y + 4}{5}$

$x = -4y + \frac{4}{5}$

Final Answer:

$x = -4y + \frac{4}{5}$

Now, let's solve for y.

Step 1) Add -5x to both sides.

$5x + 20y + - 5x = 4 + - 5x 20y = -5x + 4$

Step 2) Divide both sides by 20.

$\frac{20y}{20} = \frac{-5x + 4}{20}$

$y = \frac{-1}{4} x + \frac{1}{5}$

Final Answer:

$y = \frac{-1}{4} x + \frac{1}{5}$

Hope this helps! :D

Hint - When you have two variables in an equation, and you want to solve for one, the other will end up in your answer. :)

6 0

3 years ago

WILL GIVE BRAINLIEST. Tickets to a show cost $3 for students and $7 for adults. If 250 tickets were sold and ticket sales totale

Diano4ka-milaya [45]

Answer:

88 adult tickets were sold

Step-by-step explanation:

3s + 7a = 1102

(s + a = 250)-3

3s + 7a = 1102

+ -3s - 3a = -750 Add these equations together

4a = 352 Divide both sides by 4

a = 88

Now plug this into the second equation

s + a = 250

s + 88 = 250

- 88 - 88 Subtract 88 from both sides

s = 162

If this answer is correct, please make me Brainliest!

7 0

3 years ago

Read 2 more answers

2 1/6* 2 5/6 IN SIMPLEST FORM

andrezito [222]

Answer:

6 5/36

Step-by-step explanation:

MARK ME BRAINLIEST?

5 0

3 years ago

The A&M Hobby Shop carries a line of radio-controlled model racing cars. Demand for the cars is assumed to be constant at a

Bond [772]

Answer:

Step-by-step explanation:

A) Demand per month= 40 cars

Annual Demand (D)= 12*40 = 480

Fixed Cost per order (K)= 15

Holding Cost= 20% of cost= 60 *0.2 = 12

a. Economic Order Quantity=

Q^{*}={\sqrt {{\frac {2DK}{h}}}}

= √(2*480*15)/12

=34.64 ~ 35

Total Cost =P*D+K(D/EOQ)+h(EOQ/2) P= Cost per unit

= 60*480+ 15(480/35) + 12(35/2)

= 28800+ 205.71+ 210

=$29215.71

B). Backorder Cost (b)= $45

Qbo= Q* × √( b+h/ h)

= 35*√(12+45/ 45)

= 35* 1.12

=39.28 ~ 39

Shortage (S)= Qbo * (K/K+b)

= 39* (15/15+45)

= 39* 0.25

= 9.75

Total Cost Minimum=( bS2/ 2Qbo) + P (Qbo- S)2/2Qbo + K(D/Qbo)

=45* 9.752 / 2* 392 + 60 (39-9.75)2/ 2* 392 + 15 ( 480/39)

= 1.40+ 21.9.+ 184.61

=$207.91

C)Length of backorder days (d) = Demand ÷ amount of working days

d = 480 ÷ 300

d = 1.6

Calculate the backorders as the maximum number of backorders divided by the demand per day

s/d = 9.75/1.6 = 6.09 days (answer)

D) Calculate the difference in total between not using backorder:

$207.85 + $207.85 - 207.91 = $207.79

The saving in using backorder is $207.79.

Therefore I would recommend using a backorder

6 0

3 years ago