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Crazy boy [7]
3 years ago
5

4,0000000000×10,00000000

Mathematics
1 answer:
Mademuasel [1]3 years ago
4 0

Answer:

yes 40

Step-by-step explanation:

she got it correct

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What is the slope and y intercept of the line with equation 3x-6y=7
ruslelena [56]

Answer:

x intercept = (7/3, 0)

y intercept = (0, -7/6)

slope = 1/2

Step-by-step explanation:

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Consider the average daily winter temperature and your heating bill- is there likely to be a correlation? If so does the correla
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The answer to this is that t<span>here is a negative correlation and a causal correlation. The higher the average daily winter temperature the lower your heating bill.</span>
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The probability that Gerald makes a three-point shot in basketball is 20%. For practice, Gerald will regularly
denpristay [2]

count all the dots that are greater than 10. you'll get 6 dots. the question is asking for the dots 10 and fewer there is 40 dots in total so you subtract

40-6= 34

the answer is 34/40

6 0
3 years ago
10. Mrs. Simon is trying to find the amount of floor
luda_lava [24]
:

The area.


She is trying to find how to cover it, which would be the area of the floor.
5 0
3 years ago
From experience, it is known that on average 10% of welds performed by a particular welder are defective. if this welder is requ
bulgar [2K]
Binomial distribution can be used because the situation satisfies all the following conditions:1. Number of trials is known and remains constant (n)2. Each trial is Bernoulli (i.e. exactly two possible outcomes) (success/failure)3. Probability is known and remains constant throughout the trials (p)4. All trials are random and independent of the othersThe number of successes, x, is then given byP(x)=C(n,x)p^x(1-p)^{n-x}whereC(n,x)=\frac{n!}{x!(n-x)!}
Here we're given
p=0.10  [ success = defective ]
n=3

(a) x=0
P(x)=C(n,x)p^x(1-p)^{n-x}
=C(3,0)0.1^0(1-0.1)^{3-0}
=1(1)(0.729)
=0.729

(b) x=2
P(x)=C(n,x)p^x(1-p)^{n-x}
=C(3,2)0.1^2(1-0.1)^{3-2}
=3(0.01)(0.9)
=0.027

(c) x &ge; 2
P(x)=\sum_{x=2}^3C(n,x)p^x(1-p)^{n-x}
=P(2)+P(3)
=C(n,2)p^2(1-p)^{n-2}+C(n,3)p^3(1-p)^{n-3}
=C(3,2)0.1^2(1-0.1)^{3-2}+C(3,3)0.1^3(1-0.1)^{3-3}
=3(0.01)(0.9)+1(0.001)1
=0.027+0.001
=0.028


8 0
3 years ago
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