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ExtremeBDS [4]
3 years ago
11

which is the better estimate of the mass of a wrist watch, 50 grams or 50 kilograms. and Sandy used beachmarks to estimate that

there are more inches than feet in one yard is sandy' estimate reasonable? explain. and last one Jonathan thinks that he rides his bicycle about 4 meters from his house to school each day. is Jonathan's estimate resonable?
Mathematics
2 answers:
Neko [114]3 years ago
4 0

Answer:

1)  50 grams

2) His estimate was right.

3) Jonathan's estimate is not reasonable.

Step-by-step explanation:

1)

<em>" A wrist watch is a small watch that is attached to a bracelet or strap and is worn around the wrist "</em>

The better estimate of the mass of a wrist watch is 50 grams and not 50 kilograms because it would be very difficult for someone to wear a heavy weight thing in their wrist.

Hence answer is 50 grams.

2)

There are 36 inches in 1 yard.

and there are 3 foot in 1 yard.

Hence, Sandy's benchmark was reasonable  that there are more inches than feet in one yard.

3)

Jonathan thinks that he rides his bicycle about 4 meters from his house to school each day.

As 4 meter is not a long distance so he won't have to use his bicycle to go to school.

Hence, Jonathan's estimate is not reasonable.

Molodets [167]3 years ago
3 0
1. Unless your wristwatch is made of solid gold and weighs about 23 lbs then grams would be a better measurement.

2. Sandy's estimate is not entirely reasonable because there are 4 times as many inches in a foot than there are feet in a yard.

3. 4 meters will hardly get you across the street so I doubt Jonathan will ride his bike 4 meters to get to school.
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Step-by-step explanation:

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2 years ago
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Estimate the sum or difference.
dangina [55]

1) \frac{4}{6}+\frac{1}{8}=\frac{19}{24}

2) \frac{2}{6}+\frac{7}{8}=\frac{29}{24}

3) \frac{5}{6}-\frac{3}{8}=\frac{11}{24}

4) \frac{4}{6}+\frac{3}{8}=\frac{25}{24}

5) \frac{7}{8}-\frac{5}{6}=\frac{1}{24}

6) \frac{1}{6}+\frac{7}{8}=\frac{25}{24}

Step-by-step explanation:

In order to calculate the sum of two fractions, we first have to find the lowest common denominator of the two fractions, then multiply the numerator of each fraction by the ratio between the lowest common denominator and the original denominator, and then add/subtract the two new numerators.

1)

\frac{4}{6}+\frac{1}{8}=

Here the lowest common denominator between 6 and 8 is 24,

So we have to rewrite each fraction as having denominator 24: this means that we have to multiply both numerator and denominator of the 1st fraction by 4 (because 24/6=4), and both numerator and denominator of the 2nd fraction by 3 (because 24/8=3).

So the new numerators of the two fractions are:

4\cdot 4 = 16\\1\cdot 3 = 3

The expression then becomes:

\frac{4}{6}+\frac{1}{8}=\frac{16}{24}+\frac{3}{24}=\frac{16+3}{24}=\frac{19}{24}

2)

\frac{2}{6}+\frac{7}{8}=

Here the lowest common denominator between 6 and 8 is again 24,

so we have again to multiply both numerator and denominator of the 1st fraction by 4, and both numerator and denominator of the 2nd fraction by 3.  

So the new numerators of the two fractions are:

2\cdot 4 = 8\\7\cdot 3 = 21

And we get:

\frac{2}{6}+\frac{7}{8}=\frac{8}{24}+\frac{21}{24}=\frac{8+21}{24}=\frac{29}{24}

3)

\frac{5}{6}-\frac{3}{8}

The denominators are the same, so the lowest common denominator is always 24. So we can adopt the same procedure, and new numerators are:

5\cdot 4 = 20\\3\cdot 3 = 9

And so:

\frac{5}{6}-\frac{3}{8}=\frac{20}{24}-\frac{9}{24}=\frac{20-9}{24}=\frac{11}{24}

4)

\frac{4}{6}+\frac{3}{8}=

Using the same lowest common denominator, 24, the new numerators are:

4\cdot 4 = 16\\3\cdot 3 = 9

And so we can rewrite the expression as

\frac{4}{6}+\frac{3}{8}=\frac{16}{24}+\frac{9}{24}=\frac{16+9}{24}=\frac{25}{24}

5)

\frac{7}{8}-\frac{5}{6}=

Again, the lowest common denominator is 24. This time the denominator of the 1st fraction is 8 while the denominator of the 2nd fraction is 6, so we have to multiply the numerator of the 1st fraction by 3 and the numerator of the 2nd fraction by 4.

We get:

7\cdot 3 = 21\\5\cdot 4 = 20

So the expression will be rewritten as:

\frac{7}{8}-\frac{5}{6}=\frac{21}{24}-\frac{20}{24}=\frac{21-20}{24}=\frac{1}{24}

6)

\frac{1}{6}+\frac{7}{8}=

Here the situation is similar to the first 4 exercises: using 24 as lowest common denominator, the numerators become

1\cdot 4 = 4\\7\cdot 3 = 21

So the expression becomes

\frac{1}{6}+\frac{7}{8}=\frac{4}{24}+\frac{21}{24}=\frac{4+21}{24}=\frac{25}{24}

Learn more about fractions:

brainly.com/question/605571

brainly.com/question/1312102

#LearnwithBrainly

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astra-53 [7]

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(-7)^2-4(k+3)=49-4(k+3)>0\implies k

We can tell from the quadratic equation that C has its vertex at the point (3, 6). Also, note that

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so the furthest to the right that C extends is the point (5, 2). The line x+y=k passes through this point for 2+5=k\implies k=7. For any value of k, the line x+y=k passes through C either only once, or not at all.

So 7\le k; in set notation,

\{k\mid 7\le k

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sergeinik [125]

That would be Nets 1, 4 and 5.

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lara [203]
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