All categories

3 years ago

Please no links or fake comments, I will report.

Mathematics

2 answers:

Liono4ka [1.6K]3 years ago

8 0

Answer:

my best guess would be a because none of the others even have a constant term....

Step-by-step explanation:

A. trinomial with a constant term of 12 (correct)

B. binomial (incorrect)

C. trinomial without a constant term (incorrect)

D. that's monomial (incorrect)

If this is any way helpful, I would appreciate a brainliest :)

liq [111]3 years ago

6 0

Answer:

<h2>Option A:</h2><h2> ${y}^{5} + 13x + 12$ </h2>

Step-by-step explanation:

As,

A trinomial contains 3 terms which the above option has,

and here 12 is the constant term .

Hence,

Required option is A.

You might be interested in

QUICK QUICK! 1 MINUTE ONLY PLEASE!

Llana [10]

36 questions-----3 minutes

x questiones-----1 minutes

x=(1*36)/3

x=36/3

x=12 questions

5 0

3 years ago

Read 2 more answers

2(n+2n) what is it?i need help.

MrMuchimi

Expand the equation which gives you
2n+4n
2n+4n=6n

7 0

3 years ago

mary drew a picture of a building. she used the scale shown 1 in:16 ft. the building in her pictures 9 inches tall. what is the

MaRussiya [10]

Answer:

okay

i am not sure the answer but hi i am ok

7 0

3 years ago

What is the equation of the circle with center (0, 1) and a radius of 10?

victus00 [196]

Answer:

The equation of the circle with center (0, 1) and a radius of 10 is $\bold{x^{2} + y^{2} - 2y-99 = 0}$

Solution:

Equation of circle whose center (h, k) and radius r is given as,

$(x-h)^{2} + (y-k)^{2} = r^{2}$ ---- eqn 1

From question, given that the circle has radius 10 and center (0, 1). We have to find the equation of the circle.

Hence we get, h = 0 ; k = 1; r = 10

By using eqn 1, the equation of circle whose center (0, 1) and radius 10 is given as

$(x-0)^{2} + (y - 1)^{2} = 10^{2}$

On Simplifying we get

$x^{2} + (y-1)^{2} = 10^{2}$

Expand $(y-1)^{2}$ using the formula $(a-b)^{2} = a^{2} - 2ab + b^{2}$

$x^{2} + y^{2} - 2y + 1 = 10^{2}$

$x^{2} + y^{2} - 2y + 1 = 100$

$x^{2} + y^{2} - 2y + 1-100 = 0$

$x^{2} + y^{2}- 2y- 99 = 0$

Hence equation of the circle with center (0, 1) and a radius of 10 is $\bold{x^{2}+y^{2}-2 y-99=0}$

3 0

4 years ago

In rectangle KLMN, KM = 9x+26 and LN = 84.5. Find the value of x.

Alex777 [14]

Answer:

x = 6.5

Step-by-step explanation:

square is rectangle

9x+26 = 84.5

84.5 - 26 = 58.5

9x = 58.5

x = 58.5 divided by 9

x = 6.5

4 0

3 years ago