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2 years ago

A certain drug is made from only two ingredients: compound a and compound

Mathematics

2 answers:

qwelly [4]2 years ago

4 0

I believe it is 805.2. It is not 671

barxatty [35]2 years ago

4 0

671 milliliters where used

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for v= 4i - 5j, find unit vector u in the direction of v, and write your answer as a linear combination of the standard unit vec

umka21 [38]

Answer:

a. $u=\frac{4\sqrt{41}i }{41}-\frac{5\sqrt{41}j}{41}$

Step-by-step explanation:

The given vector is v= 4i - 5j

The magnitude of this vector is;

$|v|=\sqrt{(-4)^2+(-5)^2}$

$|v|=\sqrt{16+25}$

$|v|=\sqrt{41}$

The unit vector u in the direction of v is;

$u=\frac{v}{|v|}$

$u=\frac{4i - 5j}{\sqrt{41}}$

$u=\frac{4i }{\sqrt{41}}-\frac{5j}{\sqrt{41}}$

We rationalize to get

$u=\frac{4\sqrt{41}i }{41}-\frac{5\sqrt{41}j}{41}$

4 0

2 years ago

Read 2 more answers

What number is greater 5 or 5.01

denpristay [2]

5.01 is greater

Snsnsnsnnsjs

7 0

2 years ago

I need help with this polynomial question: (5x^5-2x)-(4x^4+3x^2). This ^ means to the power of.

jeyben [28]

Answer:

Step-by-step explanation:

5x^5 - 2x - 4x^4 - 3x^2

5x^5 - 4x^4 - 3x^2 - 2x

6 0

2 years ago

Suppose that at a state college, a random sample of 41 students is drawn, and each of the 41 students in the sample is asked to

ra1l [238]

Answer:

The confidence interval for 90% confidence would be narrower than the 95% confidence

Step-by-step explanation:

From the question we are told that

The sample size is n = 41

For a 95% confidence the level of significance is $\alpha = [100 - 95]\% = 0.05$ and

the critical value of $\frac{\alpha }{2}$ is $Z_{\frac{\alpha }{2} } =Z_{\frac{0.05 }{2} }= 1.96$

For a 90% confidence the level of significance is $\alpha = [100 - 90]\% = 0.10$ and

the critical value of $\frac{\alpha }{2}$ is $Z_{\frac{\alpha }{2} } =Z_{\frac{0.10 }{2} }= 1.645$

So we see with decreasing confidence level the critical value decrease

Now the margin of error is mathematically represented as

$E = Z_{\frac{\alpha }{2} } * \frac{s}{\sqrt{n} }$

given that other values are constant and only $Z_{\frac{\alpha }{2} }$ is varying we have that

$E\ \ \alpha \ \ Z_{\frac{\alpha }{2} }$

Hence for reducing confidence level the margin of error will be reducing

The confidence interval is mathematically represented as

$\= x - E < \mu < \= x + E$

Now looking at the above formula and information that we have deduced so far we can infer that as the confidence level reduces , the critical value reduces, the margin of error reduces and the confidence interval becomes narrower

3 0

2 years ago

The last part is function but need help asap

quester [9]

It would be the top one

4 0

2 years ago