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Harman [31]
2 years ago
13

HELP PLEASE WILL GIVE BRAINLIEST IF CORRECT

Mathematics
1 answer:
bulgar [2K]2 years ago
3 0

Answer:

<u>( -1 , -2 )</u>

Step-by-step explanation:

You might be interested in
The table shows a pattern of exponents.<br><br> What is the pattern as the exponents decrease?
Marrrta [24]

Answer:

Option C is correct.

Step-by-step explanation:

We need to find the pattern as the exponent decreases.

the first value in the table is 125.

if we divide 125 by 5 i.e 125/5 we get 25

the next value in the table is 25

if we divide 25 by 5 i.e 25/5 we get 5

the next value in the table is 5

if we divide 5 by 5 i.e 5/5 we get 1

the next value in the table is 1

if we divide 1 by 5 i.e 1/5 we get 1/5

the next value in the table is 1/5

if we divide 1/5 by 5 i.e 1/5*5 we get 1/25

the next value in the table is 1/25

So, the pattern is if we divide the previous value by 5 we get the next value in the table.

So, Option C is correct.

5 0
2 years ago
Read 2 more answers
Jim is clearing out trees and planting grass to enlarge his backyard. He plans to double both the width and the length of his cu
Ierofanga [76]
U should know the area of rectangle is w*l
if we increase it by double or times 2 its area  will be
A=2w*2wl
A=4wl
area would be 4 times of original one
Now u can get the answer
4 0
3 years ago
Here are the scores that Jenna has
amid [387]

Answer:

the variance is 6.6

sry for not showing work

5 0
2 years ago
What is 3.1666666667 as a fraction
never [62]
<span> 3 </span>1666666667⁄<span>10000000000

</span>
7 0
2 years ago
9. Alicia Martin's savings account has a principle of $1,200. It earns 6% interest compounded quartly
zavuch27 [327]

Answer:

9) \$1236.27\,10)\,\$6451.07\, 11)\,\$10,152.87 \,12)\,\$907.95 \,13)\,\$4957.69

Step-by-step explanation:

9) Since Alicia Martin's savings earns 6% quarterly for two quarters then:

A=P(1+\frac{r}{n})^{nt} ⇒ Amount (A), Principle (P), rate (r) in decimal form, number of compoundings (n) a year and t, in year or its fractions.

A=P(1+\frac{r}{n})^{nt}\Rightarrow A=1200(1+\frac{0.06}{4})^{4*\frac{1}{2}}\Rightarrow A=\$1236.27

10) Aubrey Daniel's case:

A=P(1+\frac{r}{n})^{nt}\Rightarrow A=5725(1+\frac{0.04}{4})^{4*3}\Rightarrow A\approx \$6451.07

11) As for Angelo, similarly to Alicia.

A=P(1+\frac{r}{n})^{nt}\Rightarrow A=9855(1+\frac{0.06}{4})^{4*\frac{1}{2}}\Rightarrow A\approx \$10,152.87

12) Simpson's. For semiannual n=2

A=P(1+\frac{r}{n})^{nt}\Rightarrow A=860(1+\frac{0.055}{2})^{2*1}\Rightarrow A\approx \$907.95

13) Jana Lacey amount:

A=P(1+\frac{r}{n})^{nt}\Rightarrow A=4860(1+\frac{0.04}{4})^{4*\frac{1}{2}}\Rightarrow A\approx \$4957.69

6 0
3 years ago
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