Let speed of the boat in still water = x miles per hour
Let speed of the current = y miles per hour
When water and current both flow in same direction then effective speed will be sum of both speeds that is (x+y)
now plug the given values in formula speed=distance/time
we get equation:
(x+y)=160/8
or x+y=20...(i)
When water and current both flow in opposite direction then effective speed will be difference of both speeds that is (x-y)
now plug the given values in formula speed=distance/time
we get equation:
(x-y)=160/40
or x-y=4
or x=4+y...(ii)
plug value of x into (i)
4+y+y=20
4+2y=20
2y=16
y=8
plug value of y into (ii)
x=4+8=12
Hence final answer is given by:
Speed of the boat in still water = 12 miles per hour
Speed of the current = 8 miles per hour
Answer:
350
Step-by-step explanation:
40% of 250 is 100 (10% of 250 is 25 and 25 times 4 is 100)
250+100 is 350
Answer:
<h3>600 feet</h3>
Step-by-step explanation:
<u>I would just like to explain how this works with a visual (please enjoy my drawing <3 haha)</u>
With my drawing we know that the bird is 150 feet above sea level, and the fish is 100 feet below sea level.
From the bird to the water it is 150 feet, from water to fish is 100 feet
<u>From</u><u> the </u><u>bird</u><u> to the</u><u> fish</u><u> it is </u><u>150 feet + 100 feet</u>
<h3>This is equal to
250 feet, </h3>
so we know from the bird (150 feet above sea level) to the fish(100 feet below sea level).
<h2>Knowing this information we can easily answer this question</h2><h3>
Dave is 250 feet above sea level, and he went 600 feet nelow sea level, meaning<u>
he only went 600 feet under the water.</u></h3>
Answer:
Area of big rectangle= 5m× 3m
= 15m²
Area of small rectangle=1m× 1m
=1m²
Area of shaded part= Area of big rectangle- Area of a small rectangle
= 15m²-1m²
= 14m²
Step-by-step explanation: Hope it helps