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3 years ago

15

Trey's car has a 40 gallon tank. The fuel gauge points to . If Trey buys 30 gallons of gas, what will be the new reading on the

gas gauge?

2 answers:

never [62]3 years ago

7 0

Im pretty sure is 4 over 4

12345 [234]3 years ago

4 0

I believe it would be 4/4
Which would be full

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18. Write an expression to represent the area of the shaded region in simplest form. Please help it's due tomorrow

IgorC [24]

Answer:

(x^2 + 2x - 21) sq units

Step-by-step explanation:

Area of the shaded region = Area of the larger rectangle - Area of smaller rectangle

Area of the larger region = x(x+2)

Area of the larger region =x^2 + 2x

Area of the smaller rectangle = 3 * 7

Area of the smaller rectangle = 21 sq. units

Area of the shaded region = x^2 + 2x - 21

Hence the required expression is (x^2 + 2x - 21) sq units

7 0

3 years ago

How do you simplify 420/450?

MatroZZZ [7]

<span><span>Find the GCD (or HCF) of numerator and denominator
GCD of 420 and 450 is 30</span><span>Divide both the numerator and denominator by the GCD
(420/30)/(450/30)</span><span>Reduced fraction: 14/15</span></span>

Equivalent fractions

7 0

3 years ago

Read 2 more answers

A roast turkey is taken from an oven when its temperature has reached 185 degrees F and is placed on a table in a room where the

Vedmedyk [2.9K]

(a) Using Newton's Law of Cooling, $\dfrac{dT}{dt} = k(T - T_s)$ , we have $\dfrac{dT}{dt} = k(T - 75)$ where T is temperature after T minutes.
Separate by dividing both sides by T - 75 to get $\dfrac{dT}{T - 75} = k dt$ . Integrate both sides to get $\ln|T - 75| = kt + C$ .

Since $T(0) = 185$ , we solve for C:
$|185 - 75| = k(0) + C\ \Rightarrow\ C = \ln 110$
So we get $\ln|T - 75| = kt + \ln 110$ . Use T(30) = 150 to solve for k:
$\ln| 150 - 75 | = 30k + \ln 110\ \Rightarrow\ \ln 75 - \ln 110= 30k \Rightarrow \\ k= \frac{1}{30}\ln (75/110) = \frac{1}{30}\ln(15/22)$

So

$\ln|T - 75| = kt + \ln 110 \Rightarrow |T - 75| = e^{kt + \ln110} \Rightarrow \\ \\
|T - 75| = 110e^{kt} \Rightarrow T - 75 = \pm110e^{(1/30)\ln(15/22)t} \Rightarrow \\
T = 75 \pm110e^{(1/30)\ln(15/22)t}$

But choose Positive because T > 75. Temp of turkey can't go under.

$T(t) = 75 + 110e^{(1/30)\ln(15/22)t} \\
T(45) = 75 + 110e^{(1/30)\ln(15/22)(45)} = 136.929 \approx 137{}^{\circ}F$

(b)

$T(t) = 75 + 110e^{(1/30)\ln(15/22)t} = 75 + 110(15/22)^{t/30} \\
100 = 75 + 110(15/22)^{t/30} \\
25 = 110(15/22)^{t/30} 
\frac{25}{110} = (15/22)^{t/30} \\
\ln(25/110) / ln(15/22) = t/30 \\
t = 30\ln(25/110) / ln(15/22) \approx 116\ \mathrm{min}$

Dogs of the AMS.

4 0

3 years ago

Someone help I really need it.

NeX [460]

Answer:

c

Step-by-step explanation:

6 0

3 years ago

Read 2 more answers

Please help, thank you

Trava [24]

A=h•b/2
h=2x+1
b=2x
A=(2x+1) •2x/2
Divide numerator and denominator by 2
A=x(2x+1)

5 0

3 years ago