Answer:
51,111%
Step-by-step explanation:
We know that 45% have a dog but no cat. While 23% have both a dog and a cat.
Then Pr(X has cat|X has dog) = Pr(X has dog and cat)/Pr(X has dog)
= Pr(X has dog and cat)/Pr(X has dog) = 0.23/0.45 = 0.51 ≈ 51,111%
The probability that a student’s family owns a cat if the family owns a dog is 51,111%
First, you divide the fraction, and then you multiply it by 100.
So you get:



So, 5/16 is 31.25%
Hope this Helps! :)
Answer:
(or 6.25)
Step-by-step explanation:
Let's do a simple square problem to see the relationship between the elements of the resulting equation...

As you see, the number of 'x' (6) is the double of the numeric part of the binomial expression (3), while the numeric-only part (9) is the square of the numeric part of the binomial expression (3).
So, if we look at the formula from the problem, we see the the number of 'x' is 5. To obtain the C value, we need to divide the 5 by 2... then get the square value of the result.
(or 6.25)
For the first 1 X= 11 because all you need to do is add or subtract the numbers visible.
The second would be 2.