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artcher [175]
3 years ago
5

Jenny pays $853 per month for her car payment. How much does she pay per year?

Mathematics
1 answer:
siniylev [52]3 years ago
7 0

$10236 a year for her car payments

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James has a dog grooming service. He charges a flat rate of $50 per month, plus $10 per grooming. Bradly does not charge a month
solmaris [256]

Answer:

The numbers of grooming visits for which James and Bradly would charge the same amount is 2

Step-by-step explanation:

Let

w -----> the numbers of grooming visits

y ----> the charge in dollars

we know that

<em>James</em>

y=10w+50 ----> equation A

<em>Bradly</em>

y=35w ----> equation B

equate equation A and equation B

35w=10w+50

Solve for w

35w-10w=50

25w=50

w=2

therefore

The numbers of grooming visits for which James and Bradly would charge the same amount is 2

8 0
3 years ago
Is the following true? Why or why not? 2x^3 = (2x^3)
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<span>2x^3 = (2x^3)
Yes it's true
Value won't change.</span>
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5 1/6 as 30 goes into 6 times tables, and there would be a remainder of 1
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Solve for x<br><br> A) 14<br> B) 8<br> C) 5<br> D) 10
kozerog [31]
The answer is A which 14
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If h and k are constants and x^2+kx+7 is equivalent to (x+1)(x+h), what is the value of k?
pantera1 [17]
The answer is K=(xh+x+h-7)/x
First you multiply the (X+1)(X+H) and get x^2+XH+X+H

Then you set it equal to X^2+KX+7=X^2+XH+X+H

Both X^2 CANCELS then move the 7 over by subtracting it giving you

KX=XH+X+H-7
Then divide by x giving you K by itself the answer bein K=(XH+X-H-7)/X
7 0
3 years ago
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