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kramer
3 years ago
8

Help with math hw please

Mathematics
1 answer:
Marta_Voda [28]3 years ago
8 0

Answer:

Please make sure your questions are as detailed and as specific as possible so we at Brainly can give you the best answers. Please review our policy.

Step-by-step explanation:

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For each part, give a relation that satisfies the condition. a. Reflexive and symmetric but not transitive b. Reflexive and tran
Vesnalui [34]

Answer:

For the set X = {a, b, c}, the following three relations satisfy the required conditions in (a), (b) and (c) respectively.

(a) R = {(a,a), (b,b), (c, c), (a, b), (b, a), (b, c), (c, b)} is reflexive and symmetric but not transitive .

(b) R = {(a, a), (b, b), (c, c), (a, b)} is reflexive and transitive but not symmetric .

(c) R = {(a,a), (a, b), (b, a)} is symmetric and transitive but not reflexive .

Step-by-step explanation:

Before, we go on to check these relations for the desired properties, let us define what it means for a relation to be reflexive, symmetric or transitive.

Given a relation R on a set X,

R is said to be reflexive if for every a \in X, (a,a) \in R.

R is said to be symmetric if for every (a, b) \in R, (b, a) \in R.

R is said to be transitive if (a, b) \in R and (b, c) \in R, then (a, c) \in R.

(a) Let R = {(a,a), (b,b), (c, c), (a, b), (b, a), (b, c), (c, b)}.

Reflexive: (a, a), (b, b), (c, c) \in R

Therefore, R is reflexive.

Symmetric: (a, b) \in R \implies (b, a) \in R

Therefore R is symmetric.

Transitive: (a, b) \in R \ and \ (b, c) \in R but but (a,c) is not in  R.

Therefore, R is not transitive.

Therefore, R is reflexive and symmetric but not transitive .

(b) R = {(a, a), (b, b), (c, c), (a, b)}

Reflexive: (a, a), (b, b) \ and \ (c, c) \in R

Therefore, R is reflexive.

Symmetric: (a, b) \in R \ but \ (b, a) \not \in R

Therefore R is not symmetric.

Transitive: (a, a), (a, b) \in R and (a, b) \in R.

Therefore, R is transitive.

Therefore, R is reflexive and transitive but not symmetric .

(c) R = {(a,a), (a, b), (b, a)}

Reflexive: (a, a) \in R but (b, b) and (c, c) are not in R

R must contain all ordered pairs of the form (x, x) for all x in R to be considered reflexive.

Therefore, R is not reflexive.

Symmetric: (a, b) \in R and (b, a) \in R

Therefore R is symmetric.

Transitive: (a, a), (a, b) \in R and (a, b) \in R.

Therefore, R is transitive.

Therefore, R is symmetric and transitive but not reflexive .

4 0
3 years ago
Please answer this correctly
mr Goodwill [35]

Answer:

4/5 chance

Step-by-step explanation:

There are 4 numbers that fit the rule, 1, 3, 4, 5, since all of them are either odd or greater than 3. There will be a 4/5 chance of picking one.

4 0
3 years ago
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Which statements prove that a quadrilateral is a parallelogram?
Arte-miy333 [17]

Answer:

It is the Quadrilateral DEFG has only one set of opposite angles that are congruent and Quadrilateral DEFG has one diagonal that bisects the other diagonal.

Step-by-step explanation:

4 0
3 years ago
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The cost to rent a video game for 3 days was $10. It costs the same amount each day.
Norma-Jean [14]
¢30 every day because 10divided by 3 is .3
6 0
3 years ago
Jennifer has 7 marbles in her bag. She has 4 blue, 1 white, 1 pink, and 1 yellow. She chooses one marble without looking. What i
lesantik [10]

In Jennifer's bag, there are 7 marbles. Out of 7 marbles, 4 of them are blue.

Hence, the probability that Jennifer picks one blue marble is 4/7. (Option 1).

3 0
1 year ago
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