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Anton [14]
3 years ago
13

How do i factorise this equation 25x²-p²

Mathematics
1 answer:
kondaur [170]3 years ago
6 0

You can write it in the form a^2 - b^2 where a = 5x and b = p

(5x)^2 - p^2

And then use the Difference of Squares a^2 - b^2 = (a + b)(a - b)

Answer is (5x + p)(5x - p)

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Solve for x enter the solutions from the least to greatest x2+7=43 lesser x= Greater x=
Snowcat [4.5K]

Answer:

x = ±6

Step-by-step explanation:

Step 1: Write out equation

x² + 7 = 43

Step 2: Subtract 7 on both sides

x² = 36

Step 3: Square root both sides

√x² = √36

x = ±6

7 0
3 years ago
Complete the statement. Round to the nearest hundredth if necessary<br> 18 ft = { }yd
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Anyone know how to solve this?
Dmitry_Shevchenko [17]

Answer:

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Step-by-step explanation:

7 0
3 years ago
3(2x) + 3(-1) = -21 <br><br>6x - 3 = -21<br> What property is being used ?
kaheart [24]
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4 0
3 years ago
A train leaves San Diego at 1:00 pm. A second train leaves the same city in the same direction at 3:00 pm. The second train trav
Soloha48 [4]

Answer:

The speed of the first train is 45 mph and the speed of the second train is 75 mph

Step-by-step explanation:

Let x represent the speed of the first train in mph. Since the second train, is 30 mph faster then the first, therefore the speed of the second train is (x + 30).

The first train leaves at 1:00 pm, therefore at 6:00 pm, the time taken is 5 hours. Therefore the distance covered by the first train at 6:00 pm = x mph * 5 hours = 5x miles

The second train leaves at 3:00 pm, therefore at 6:00 pm, the time taken is 3 hours. Therefore the distance covered by the second train at 6:00 pm = (x + 30) mph * 3 hours = (3x + 90) miles

Since the second train overtakes the first at 6:00 pm, hence:

3x + 90 = 5x

2x = 90

x = 45

Therefore the speed of the first train is 45 mph and the speed of the second train is 75 mph (45 mph + 30 mph).

7 0
3 years ago
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