A wire is attached at the top of a 500 ft vertical antenna and is staked in the ground 1200 ft from the base of the antenna. how
1 answer:
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Answer:
35%
Step-by-step explanation:
easy way to remember:
=
= 35%
Answer:
86in²
Step-by-step explanation:
Find the complete question attached
Area of the circle = πr²
Area of the square = L²
Length of the side of the square
r is the radius of the circle
r = L/2 = 20/2 =10in
Given
Length of the side of the circle = 20in
Area of the square = 20²
Area of the square = 400in²
Area of the circle =π(10)²
Area of the circle = 3.14(100)
Area of the circle= 314in²
Amount of plywood left over = 400in²-314in² = 86in²
We need to find the center and the radius of
The general circle equation is the following
where
(h,k) is the center and
r is the radius
1. rearrange the equation
2. Add 25 on both sides
3. Factor
Now we have an equation that is very similar to the circle equation, so let's compare them
Center -> (h,k) = (5,-11)
radius -> r = 5
Since there is no picture shown, I just plotted the given data points myself. That is shown in the attached picture. The blue rectangle is rectangle PQRS while the orange one is rectangle JKLM. I believe there are some choices for this question but you forgot to include. Nevertheless, I will give my observations from the given figure.
The tile PQRS is bigger than tile JKLM. A rectangle is a two-dimensional shape that has two sets of equal parallel planes. Thus, its area is equal to the length multiplied by its width.
tile PQRS = (9-5)*(12-7) = 20 units²
tile JKLM = (6-4)*(10-5) = 10 units²
Tile PQRS is larger by 10 units².
The tile PQRS is bigger than tile JKLM. A rectangle is a two-dimensional shape that has two sets of equal parallel planes. Thus, its area is equal to the length multiplied by its width.
tile PQRS = (9-5)*(12-7) = 20 units²
tile JKLM = (6-4)*(10-5) = 10 units²
Tile PQRS is larger by 10 units².