The measure of an angle<span> formed by a </span>secant<span> and a </span><span>tangent </span><span>drawn from a point outside the </span>circle<span> is half the the difference of the </span>intercepted arcs<span>.
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Let P be the last point in the triangle you have drawn from AB.. It is isosceles and rectangle hence AB^2=2BP^2 hence AP=BP=sqrt(2).
Let Q be the last point in the triangle you have drawn from CD. By the same reasoning, CQ=DQ=sqrt(2)
What is more, AD=AP+PQ+QD=2sqrt(2)+1
Answer: The answer is -4
Step-by-step explanation:−40=12x+8
Step 1: Flip the equation.
12x+8=−40
Step 2: Subtract 8 from both sides.
12x+8−8=−40−8
12x=−48
Step 3: Divide both sides by 12.
12x
12
=
−48
12
x=−4
Answer:
x=−4
Can you please be more specific?
