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Mrac [35]
3 years ago
5

ABC is reflected across x = 1 and y = -3. What are the coordinates of the reflection image of B after both reflections?A. (-7, -

1)B. (-7, 1)C. (7, 1)D. (7, -1)

Mathematics
1 answer:
Dima020 [189]3 years ago
8 0

Answer:

The correct option is C.

Step-by-step explanation:

From the given figure it is noticed that the coordinates of B are (-5,-7).

If ABC is reflected across x = 1, then

(x,y)\rightarrow(1-(x-1),y)

(x,y)\rightarrow(2-x,y)

(-5,-7)\rightarrow(2+5,-7)

(-5,-7)\rightarrow(7,-7)

If ABC is reflected across y =-3.

(x,y)\rightarrow(x,-3-(y-(-3)))

(x,y)\rightarrow(x,-6-y)

(7,-7)\rightarrow(7,-6-(-7))

(7,-7)\rightarrow(7,1)

Therefore option C is correct.

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Answer:

The equation of the straight line in point-slope form

                            y - 4 = \frac{7}{9}  (x-0)

The equation of the straight line

                         7x -9y +36 =0

Step-by-step explanation:

<u><em>Step(i):-</em></u>

Given that the points (0,4) and (-9,-3)

The slope of the line

         m = \frac{y_{2} - y_{1} }{x_{2}- x_{1}  } = \frac{-3-4}{-9-0} = \frac{7}{9}

<u><em>Step(ii):-</em></u>

    Equation of the straight line passing through the point (0,4) and having slope m = 7/9

          y - y_{1} = m (x-x_{1} )

         y - 4 = \frac{7}{9}  (x-0)

      9 y - 36 = 7x

              9y = 7x + 36

          y = \frac{7x}{9} +\frac{36}{9}

Slope - intercept form  

                            y = \frac{7x}{9} +4

<u><em>Final answer:-</em></u>

The equation of the straight line in point-slope form

                            y - 4 = \frac{7}{9}  (x-0)

The equation of the straight line

                         7x -9y +36 =0

           

   

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