Question

What are the roots of the equation 2x2 - 6x + 3 = 0?

Answer 1

Answer:

Step-by-step explanation:

The given possible roots have the form that we'd get by using the quadratic formula, so let's start with that.  Here the coefficients are {2, -6, 3}, and so the discriminant (b^2 - 4ac) is (-6)^2 - 4(2)(3), or 36 - 24 = 12.

Because the discriminant is positive we know immediately that there are two different real roots.

      -(-6) ± √12         6 ± √12

x = ------------------ = ----------------     These are equivalent to Answers E and F.

            2(2)                    4

Answer 2

Answer:

Step-by-step explanation: