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2 years ago

Heelp. I will give brainliest to whoever answers correctly.-

Mathematics

1 answer:

Rudik [331]2 years ago

5 0

Answer:

Deliah: 1701/9=189

Dakoda: 1479/9=164.33

Coach should choose Deliah.

Step-by-step explanation:

mean= all the numbers added up/ how many numbers there are

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Explain why f(x) =√2+x - √2/x, is not continuous at x = 0.<br> Picture provided below.

IrinaK [193]

Answer: A

Step-by-step explanation:

If you put 0 in for x, then you would be dividing by 0. Dividing by 0 is always undefined.

3 0

3 years ago

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PLEASE AND THANK YOU CONFUSED ON THIS

ICE Princess25 [194]

After staring at this for a few seconds, I think the equation

$-5\sqrt{10}\cdot\sqrt{15}=[1]\sqrt{[2]}$

is asking you to simplify the left hand side so that it has a form matching the right hand side, and [1] and [2] are placeholders. My guess is that they're supposed to be integers.

Notice that

$\sqrt{10}=\sqrt{5\cdot2}=\sqrt5\cdot\sqrt2$

$\sqrt{15}=\sqrt{5\cdot3}=\sqrt5\cdot\sqrt3$

$\implies\sqrt{10}\cdot\sqrt{15}=(\sqrt5)^2\cdot\sqrt2\cdot\sqrt3=5\sqrt{2\cdot3}=5\sqrt6$

Then multiplying by -5, we have

$-5\sqrt{10}\cdot\sqrt{15}=-25\sqrt6$

so I believe [1] = -25, and [2] = 6.

5 0

2 years ago

Need help with Calculus 1 inverse trig functions

lidiya [134]

Answer:

$\displaystyle y'=3\frac{1+\frac{x}{\sqrt{1+x^2}}}{2+2x^2+2x\sqrt{1+x^2}}$

Step-by-step explanation:

<u>The Derivative of a Function</u>

The derivative of f, also known as the instantaneous rate of change, or the slope of the tangent line to the graph of f, can be computed by the definition formula

$\displaystyle f'(x)=\lim\limits_{\Delta x \rightarrow 0}\frac{f(x+\Delta x)-f(x)}{\Delta x}$

There are tables where the derivative of all known functions are provided for an easy calculation of specific functions.

The derivative of the inverse tangent is given as

$\displaystyle (tan^{-1}u)'=\frac{u'}{1+u^2}$

Where u is a function of x as provided:

$y=3tan^{-1}(x+\sqrt{1+x^2})$

If we set

$u=(x+\sqrt{1+x^2})$

Then

$\displaystyle u'=1+\frac{2x}{2\sqrt{1+x^2}}$

$\displaystyle u'=1+\frac{x}{\sqrt{1+x^2}}$

Taking the derivative of y

$y'=3[tan^{-1}(x+\sqrt{1+x^2})]'$

Using the change of variables

$\displaystyle y'=3[tan^{-1}u]'=3\frac{u'}{1+u^2}$

$\displaystyle y'=3\frac{u'}{1+u^2}=3\frac{1+\frac{x}{\sqrt{1+x^2}}}{1+(x+\sqrt{1+x^2})^2}$

Operating

$\displaystyle y'=3\frac{1+\frac{x}{\sqrt{1+x^2}}}{1+x^2+2x\sqrt{1+x^2}+1+x^2}$

$\boxed{\displaystyle y'=3\frac{1+\frac{x}{\sqrt{1+x^2}}}{2+2x^2+2x\sqrt{1+x^2}}}$

8 0

2 years ago

Can you simplify 2.8(3-0.8)

leonid [27]

No you can not simplify

4 0

3 years ago

6. 4p + 5 - 7p = -1

Ivenika [448]

Answer: p=2

Step-by-step explanation: The first thing you should do is combine any like terms. For you this means combining 4p and -7p. This gives you -3p+5=-1. Then, subtract 5 on each side to eliminate the 5. This gives you -3p=-6. Divide by -3 on each side to allow the p to stand alone. This makes p=2.

8 0

2 years ago

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