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3 years ago

To solve the equation 2 1/8 = 3 4 + w

Mathematics

1 answer:

Anestetic [448]3 years ago

3 0

Answer:

1.375w

Step-by-step explanation:

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At an amusement park, only 18 peopel are allowed on a ride at the same tome. There are 157 people waiting in line. Hiw many grou

Bond [772]

Answer:

8 groups

Step-by-step explanation:

just keep taking away 18 till u can't anymore

your welcome

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3 years ago

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A bathtub can hold up to 110 gallons of water. The bathtub now contains 78

Irina18 [472]

Answer: (B) 30 gallons.

Step-by-step explanation: Lets subtract 110 - 78 to find the maximum amount of additional water, w that can be added to the tub.

110 - 78 = 32.

round 32 to 30.

So, a reasonable value would be 30 gallons.

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The reason we solve systems of equation is to find where the equation

muminat

Answer:

Yes

Step-by-step explanation:

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3 years ago

. If α and β are the roots of

Lostsunrise [7]

Answer:

$18x^2+85x+18 = 0$

Step-by-step explanation:

Given Equation is

=> $2x^2+7x-9=0$

Comparing it with $ax^2+bx+c = 0$ , we get

=> a = 2, b = 7 and c = -9

So,

Sum of roots = α+β = $-\frac{b}{a}$

α+β = -7/2

Product of roots = αβ = c/a

αβ = -9/2

Now, Finding the equation whose roots are:

α/β ,β/α

Sum of Roots = $\frac{\alpha }{\beta } + \frac{\beta }{\alpha }$

Sum of Roots = $\frac{\alpha^2+\beta^2 }{\alpha \beta }$

Sum of Roots = $\frac{(\alpha+\beta )^2-2\alpha\beta }{\alpha\beta }$

Sum of roots = $(\frac{-7}{2} )^2-2(\frac{-9}{2} ) / \frac{-9}{2}$

Sum of roots = $\frac{49}{4} + 9 /\frac{-9}{2}$

Sum of Roots = $\frac{49+36}{4} / \frac{-9}{2}$

Sum of roots = $\frac{85}{4} * \frac{2}{-9}$

Sum of roots = S = $-\frac{85}{18}$

Product of Roots = $\frac{\alpha }{\beta } \frac{\beta }{\alpha }$

Product of Roots = P = 1

The Quadratic Equation is:

=> $x^2-Sx+P = 0$

=> $x^2 - (-\frac{85}{18} )x+1 = 0$

=> $x^2 + \frac{85}{18}x + 1 = 0$

=> $18x^2+85x+18 = 0$

This is the required quadratic equation.

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3 years ago

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What is the shape 1 circular base and 1curved surface

swat32

Circular based pyramid I believe

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