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Ede4ka [16]
2 years ago
13

A square with vertices (5, 0) and (0, -5) with a side length of 5 units​

Mathematics
1 answer:
Lyrx [107]2 years ago
7 0

Answer:

whats the question that is a statement

Step-by-step explanation:

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Simplify: 6(5x - 2) - (3x - 4)​
Sloan [31]

Answer:

27x-8

Step-by-step explanation:

6(5x-2)-(3x-4)\\30x-12-3x+4\\27x-8

7 0
2 years ago
Read 2 more answers
Which ordered pair is a solution to the inequality?<br><br> Help please!!
Murrr4er [49]

Choice A is the answer which is the point (1,-1)

=========================================

How I got this answer:

Plug each point into the inequality. If you get a true statement after simplifying, then that point is in the solution set and therefore a solution. Otherwise, it's not a solution.

-------------

checking choice A

plug in (x,y) = (1,-1)

y - 2x \le -3

-1 - 2(1) \le -3

-3 \le -3

This is true because -3 is equal to itself. So this is the answer.

-------------

checking choice B

plug in (x,y) = (2,4)

y - 2x \le -3

4 - 2(2) \le -3

0 \le -3

This is false because 0 is not to the left of -3, nor is 0 equal to -3. We can cross this off the list.

-------------

checking choice C

plug in (x,y) = (-2,3)

y - 2x \le -3

3 - 2(-2) \le -3

7 \le -3

This is false because 7 is not to the left of -3, nor is 7 equal to -3. We can cross this off the list.

-------------

checking choice D

plug in (x,y) = (3,4)

y - 2x \le -3

4 - 2(3) \le -3

-2 \le -3

This is false because -2 is not to the left of -3, nor is -2 equal to -3. We can cross this off the list.


4 0
3 years ago
Find the distance between the pair of points (-3, 1) and (2, 1)
BARSIC [14]
The answer to your question is 5
3 0
3 years ago
Read 2 more answers
Solve for x in the diagram below.
bija089 [108]

Answer:

x = 12

Step-by-step explanation:

20° + (6x - 2) = 90°

18° + 6x = 90°

6x = 90° - 18°

6x = 72°

x = 72°/6

x = 12

8 0
3 years ago
Read 2 more answers
Write the following quotient in the form a+bi.<br> -7i/2-7i
Helga [31]

Answer:

\large\boxed{\dfrac{49}{53}-\dfrac{14}{53}i}

Step-by-step explanation:

\text{Use}\\\\i=\sqrt{-1}\to i^2=-1\\\\(a-b)(a+b)=a^2-b^2\to(a-bi)(a+bi)=a^2+b^2\\\\\text{distributive property}\ a(b+c)=ab+ac\\---------------------\\\\\dfrac{-7i}{2-7i}=\dfrac{-7i}{2-7i}\cdot\dfrac{2+7i}{2+7i}=\dfrac{-7i(2+7i)}{2^2+7^2}=\dfrac{(-7i)(2)+(-7i)(7i)}{4+49}\\\\=\dfrac{-14i-49i^2}{53}=\dfrac{-14i-49(-1)}{53}=\dfrac{-14i+49}{53}\\\\=\dfrac{49}{53}-\dfrac{14}{53}i

8 0
3 years ago
Read 2 more answers
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