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3 years ago

Which of the following ordered pair could NOT be included in this set if it is a function? { (-4, 2), (3, 6), (4, 3), (?, ?) }

Mathematics

1 answer:

pantera1 [17]3 years ago

7 0

Answer:

I´m pretty sure it´s 2.(-3,6).

Step-by-step explanation:

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3 years ago

Solve for the missing angle measure x.

Romashka-Z-Leto [24]

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Step-by-step explanation:

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3 years ago

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Solve Q²= a(p²-b²)/p in form of y=mx+c

umka2103 [35]

Answer:

We want to rewrite:

q^2 = a*(p^2 - b^2)/p

as a linear equation, in the form:

y = m*x + c

So we start with:

q^2 = a*(p^2 - b^2)/p

we can expand the left side to get:

q^2 = (a/p)*p^2 - (a/p)*b^2

q^2 = a*p - (a/p)*b^2

Now we can ust define:

a*p = c

Then we can replace that to get:

q^2 = -(a/p)*b^2 + c

now we can replace:

q^2 = y

b^2 = x

Replacing these, we get:

y = -(a/p)*x + c

finally, we can replace:

-(a/p) = m

then we got the equation:

y = m*x + c

where:

y = q^2

x = b^2

c = a*p

m = -(a/p)

4 0

3 years ago

A piece of fabric is 1/3 yard by 3 5/8 yards.

tankabanditka [31]

Answer:

sorry if this is wrong

Step-by-step explanation:

a. 3

b.15

c.8

3 0

3 years ago

Carl can paint a room 3 hours faster than Jennifer can

Nata [24]

Jen take x hours.
Carl (x-3)hours.
Jen+carl take two hours;
This means;
In 1 hour, for they work
$\frac{1}{x} + \frac{1}{x-3}$
= $\frac{(x-3)+x}{x(x-3)}$
= $\frac{2x-3}{x(x-3)}$
Working together, they take two hours;
Take reciprocal of above equation and equate to two;
= $\frac{x(x-3)}{2x-3} =2$
$x^{2}$ -3x=4x-6
$x^{2} -7x+6=0$
$x^{2}$ -x-6x+6=0
x(x-1)-6(x-1)=0
(x-6)(x-1)=0
Take the bracket x-6=0 so that Carl works positive hours
x-6=0
x=6

8 0

3 years ago