Answer with explanantion:
1. What is asked? <u>The smallest number of eggs that Mang Andoy can put using the tray.</u>
2. What are given facts? <u>Two kinds of tray (One can have 6 eggs , other can have 12 eggs)</u>
3. How will you solve the problem? <u>We need to find LCM of 6 and 12</u>.
4. How is the solution done?
<u>Prime factorization of 6 and 12:</u>
<u>6=2 x 3</u>
<u>12 = 2 x 2 x 3</u>
<u>LCM(6,12) = 2 x 2 x 3 = 12</u>
5. What is the answer to the problem?<u> The smallest number of eggs that Mang Andoy can put using the tray = 12</u>
Answer:
showing bellow
Step-by-step explanation:
Let me use an exsample to show this.
Nash is making a framed enlargement of a Mary Cassatt postage stamp to present to a retired postmaster. He enlarges the stamp using a scale of 2 inches to 1 centimeter. If the actual length of the stamp is 3 centimeters and its width is 5 centimeters, what are the dimensions of the scale picture?
6 inches by 10 inches
Step-by-step explanation:
It tells us that the scale is 2 In: 1 cm so we know that for every centimeter long or wide the stamp is the enlardged scale is two inches.
2 times 3 is 6. 6 inches. we are multiplying two inches by the number of centimeter long it is.
5 times 2 is 10 inches. we are multiplying two inches by the number of centimeter wide it is.
therefore the enlarged stamp is 6 In by 10 In.
Hope this helps :)
Answer:
√(4/5)
Step-by-step explanation:
First, let's use reflection property to find tan θ.
tan(-θ) = 1/2
-tan θ = 1/2
tan θ = -1/2
Since tan θ < 0 and sec θ > 0, θ must be in the fourth quadrant.
Now let's look at the problem we need to solve:
sin(5π/2 + θ)
Use angle sum formula:
sin(5π/2) cos θ + sin θ cos(5π/2)
Sine and cosine have periods of 2π, so:
sin(π/2) cos θ + sin θ cos(π/2)
Evaluate:
(1) cos θ + sin θ (0)
cos θ
We need to write this in terms of tan θ. We can use Pythagorean identity:
1 + tan² θ = sec² θ
1 + tan² θ = (1 / cos θ)²
±√(1 + tan² θ) = 1 / cos θ
cos θ = ±1 / √(1 + tan² θ)
Plugging in:
cos θ = ±1 / √(1 + (-1/2)²)
cos θ = ±1 / √(1 + 1/4)
cos θ = ±1 / √(5/4)
cos θ = ±√(4/5)
Since θ is in the fourth quadrant, cos θ > 0. So:
cos θ = √(4/5)
Or, written in proper form:
cos θ = (2√5) / 5
I search and found different answers but the nearest is 24
