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3 years ago

Jacob used 1/7 of a liter of water to fill 1/9 of the fish aquarium. How many liters r needed to fill the aquarium?

2 answers:

8 0

We know that 1/7 of a liter filled up 1/9 of the aquarium, well, a "whole" will be 9/9.

how many liters will it be to fill up the 9/9 of the aquarium?

$\bf \begin{array}{ccll}
\stackrel{liters}{water}&\stackrel{fish}{aquarium}\\
\text{\textemdash\textemdash\textemdash}&\text{\textemdash\textemdash\textemdash}\\
\frac{1}{7}&\frac{1}{9}\\\\
w&\frac{9}{9}
\end{array}\implies \cfrac{\frac{1}{7}}{w}=\cfrac{\frac{1}{9}}{\frac{9}{9}}\implies 
\cfrac{\frac{1}{7}}{\frac{w}{1}}=\cfrac{\frac{1}{9}}{\frac{9}{9}}\implies 
\cfrac{1}{7}\cdot \cfrac{1}{w}=\cfrac{1}{9}\cdot \cfrac{9}{9}
\\\\\\
\cfrac{1}{7w}=\cfrac{1}{9}\implies 9=7w\implies \cfrac{9}{7}=w$

Zinaida [17]3 years ago

6 0

Since 1/7 L of water fills 1/9 of the aquarium, 9 times 1/7 will fill the aquarium:

9(1/7) = 9/7 = 1 2/7 L of water will fill the aquarium.

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nataly862011 [7]

Answer:

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Step-by-step explanation:

Let x represents the number of nights Jack worked and y represents the number of nights Diane worked.

1. The number of nights Diane is scheduled to work is no more than four times the number of nights Jack is scheduled to play. Then

$y\le 4x$

2. Diane will work at least 10 times before the concert. Then

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3. Jack earns $50 per night that he plays, then he earned $50x in x nights. Diane earns $25 each night she works, then she earns $25y in y nigths. They need at least $750, so

$50x+25y\ge 750$

4. We get the following set of constraints to model the problem:

$\left\{\begin{array}{l}y\le 4x\\ \\x\ge 10\\ \\50x+25y\ge 750\end{array}\right.$

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Montano1993 [528]

Answer:

Step-by-step explanation:

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nikitadnepr [17]

Answer:

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Solution:

As per the question:

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Now, suppose the $T_{i}$ is the time between the departure of the rider i - 1 and i from the cable car.

where

$T_{i}$ = independent exponential random variable whose rate is $\lambda$

The general form is given by:

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$S_{n} = f(t:n, \lamda) = \frac{\lambda^{n}e^{- \lambda t}t^{n - 1}}{(n - 1)!}$

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