Answer:
a) The equation is:
Confidence Interval = Mean ± Z score × Standard deviation/√Number of samples
b) The 98% confidence interval = (5.62784, 6.37216)
Step-by-step explanation:
a. Write down the equation you should use to construct the confidence interval for the average number of days absent per term for all the children. (10 points)
Confidence Interval = Mean ± Z score × Standard deviation/√Number of samples
b. Determine a 98% confidence interval estimate for the average number of days absent per term for all the children. (10 points)
Confidence Interval = Mean ± Z score × Standard deviation/√Number of samples
Mean = 6 days
Standard deviation = 1.6 days
Number of samples = 100
Z score of 98% confidence interval = 2.326
Confidence interval = 6 ± 2.326 × 1.6/√100
= 6 ± 2.326 × 1.6/10
= 6 ± 0.37216
= 6 - 0.37216
= 5.62784
6 + 0.37216
= 6.37216
Therefore, the 98% confidence interval = (5.62784, 6.37216)
The mixture contains 61.5% of water.
<u>Step-by-step explanation:</u>
Total parts = 4+ 2.5 = 6.5
Parts of water =4
parts of drink = 2.5
Percent of water in the mixture = 4 × 100/ 6.5
= 400/6.5
= 61.53%
It is rounded to the nearest tenth as 61.5%.
28/57*100=49% I would like to think that is the correct procedure and answer
Answer:
I think u forgot to put a photo because I really don't understand
Step-by-step explanation:
not sure
