If the length of a rectangle is 5a^2 and the width is 7ab^2 what is the area of the rectangle?
1 answer:
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Answer:
x = 52°
Step-by-step explanation:
I have attached an image to depict the given angles.
From the attached image, we can see that the unknown angle is x°.
Thus, since that corner is 90°, then;
x + 38 = 90
Subtract 38 from both sides to get;
x = 90 - 38
x = 52°
