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Nutka1998 [239]
3 years ago
15

Give each trig ratio as a fraction in simplest form

Mathematics
1 answer:
Volgvan3 years ago
5 0
Sin D is 21/29
cos D is 20/29
tan D is 21/20
sin E 20/29
cos E is 21/29
tan E is 20/21

sin is y/r
cos is x/r
tan is y/x

Two different perspectives of the triangle, D and E.
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Can someone help me with this ASAP please?
svetoff [14.1K]

Answer:

x=-1 y=1/2

Step-by-step explanation:

do you need the step by step?

8 0
2 years ago
What is dy/dx if y = (x2 + 2)3(x3 + 3)2? A. 3(x2 + 2)2(x3 + 3)2 + 2(x2 + 2)2(x3 + 3) B. 2x(x3 + 3)2 + 3x2(x2 + 2)3 C. 6x(x2 + 2)
Vlada [557]
We want to find \displaystyle{  \frac{dy}{dx}, for

            \displaystyle{ y=(x^2+2)^3(x^3+3)^2.

Recall the product rule: for 2 differentiable functions f and g, the derivative of their product is as follows:

                                  (fg)'=f'g+g'f.

Thus,

 y'=[(x^2+2)^3]'[(x^3+3)^2]+[(x^3+3)^2]'[(x^2+2)^3]\\\\ =3(x^2+2)^2(x^3+3)^2+2(x^3+3)(x^2+2)^3

Answer: A)      3(x^2+2)^2(x^3+3)^2+2(x^3+3)(x^2+2)^3.



8 0
3 years ago
A motor club has estimated that a 325 mile car trip will take 6 1/2 hours. What is the club assuming to be the average speed mil
In-s [12.5K]

<u>Answer: </u>

The average speed that the club is assuming is 50 miles per hour

<u>Solution: </u>

We know that Distance = Speed × Time.

Here it is given that distance is 325 miles and the time to cover 325 miles is 6_{2}^{1} hours which is equal to \frac{13}{2} hours.

Now to find the average speed mile per hour we use the formula

\begin{aligned} \text { Speed } &=\frac{\text { Distance }}{\text { time }} \\ &=\frac{325}{\frac{13}{2}} \\ &=\frac{325 \times 2}{13} \end{aligned}

By cancelling 325 by 13 we get 25

= 25 × 2  

= 50 miles per hour

Thus the average speed that the club is assuming is 50 miles per hour.

3 0
3 years ago
Solve for x 1/2(x-3)=1/3(1-x)
Goshia [24]

Answer:

x=2.5906672908862554,−0.2573339575529219

7 0
2 years ago
Vacation Property Rentals purchased 50 television sets for their rental units at a cost of $250 per television. The televisions
Alex787 [66]
Under A straight line basis which is a method of computing depreciation and amortization by dividing the difference between an asset's cost and its expected salvage value by the number of years it is expected to be used. Also known as straight line depreciation or straight line amortization, this is the simplest depreciation method. But instead of that find The rate of depreciation
100/5 years=20% depreciation rate per year
Total cost 250×50=12,500
Salvage value 40×50=2,000
Subtract the salvage value from the total cost of televisions
12,500−2,000=10,500
In the first year the depreciation is
10,500×0.2=2,100
Book value
12,500−2,100=10,400
In the second year the depreciation is
10,500×0.2=2,100
Book value
10,400−2,100=8,300
In the third year the depreciation is
10500×0.2=2100
Book value
8300-2100=6200

the book value for all of the televisions at the end of the third year is 6200
8 0
3 years ago
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