Ans67
Step-by-step explanation:
Answer:
#15) B. 30 mn^5
#17) B. 1/2
Step-by-step explanation:
<h2>#15:</h2>
The area of a trapezoid is given in the formula: 1/2(a + b) * h, where a is the length of the top of the trapezoid, b is the length of the bottom of the trapezoid, and h is the height of the trapezoid.
All of these measurements are given so all that you need to do is to substitute these values into the formula.
Substitute 3 for a, 9 for b, and 5 for h.
Solve inside the parentheses first. Add 3 and 9.
Multiply 12 and 1/2 together.
Multiply 6 and 5.
We need to figure out if the area is to the 5th or 6th power. When we added 3 and 9 together, we combined like terms so the exponent stayed to the 3rd power.
After multiplying this ^3 by the 5mn^2, the exponent becomes to the 5th power because you add exponents when multiplying.
Therefore the final answer is B. 30 mn^5.
<h2>#17:</h2>
When going down from 32 to 8 to 2, you can see that each number is being divided by 4.
32 / 4 = 8...
8 / 4 = 2...
So to find the next number in this sequence you would divide 2 by 4.
The answer is B. 1/2.
For the answer to the question above, I believe the answer is simply <u><em>8.
</em></u>
2 groups divided into four participants. So all in all people needed is 8.
I hope this helped you. Have a nice day!
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Answer:
Step-by-step explanation:
If the roots are 1 + 5i and 1 - 5i, then you need the factors that result from those roots. They are (x - 1 + 5i) and (x - 1 - 5i). Now what you do with those is FOIL them out. Doing that gives you the following:
(what a mess, huh?)
The good thing is that several of those terms cancel each other out. +5ix cancels out the -5ix; -5i cancels out the 5i; and the 2 -x terms combine to -2x. That leaves you with:
Obviously you're in the section in math that deals with complex (imaginary) numbers so you should know that i-squared is equal to -1. Making that replacement:
a = 1, b = -2, c = 25
The answer oils be 2 square root 2 because 4 times 2 is 8 and because the square root of 4 is 2 you would move that 2 to the outside and keep the other two on the inside of the square root.
