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NNADVOKAT [17]
2 years ago
14

Answer the question you hopeless heathens

Mathematics
1 answer:
MakcuM [25]2 years ago
5 0

Answer:

A) 64x + 285 = 605

B) 5 hours

Step-by-step explanation:

64x + 285 = 605

64x + 285-285 = 605 - 285

64x = 320

64x/64 = 320/64

x = 5

Double check

($605 Total - $285 parts) / $64 Hourly rate = Labor per hour

$320 Labor / $64 Hour = 5 hours

or 64x

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Eleman sayısı 2 arttırıldığında alt küme sayısı 24 artan bir kümenin eleman sayısı kaçtır​
Lera25 [3.4K]

Answer:

What?

Step-by-step explanation:

3 0
3 years ago
Answer the following question about the function whose derivative is given below
Komok [63]

Answer:

a) The critical points are x = 3 and x = -6.

b) f is decreasing in the interval (-\infty, -6)

f is increasing in the intervals (-6,3) and (3,\infty).

c) Local minima: x = -6

Local maxima: No local maxima

Step-by-step explanation:

(a) what are the critical points of f?

The critical points of f are those in which f^{\prime}(x) = 0. So

f^{\prime}(x) = 0

(x-3)^{2}(x+6) = 0

So, the critical points are x = 3 and x = -6.

(b) on what intervals is f increasing or decreasing? (if there is no interval put no interval)

For any interval, if f^{\prime} is positive, f is increasing in the interval. If it is negative, f is decreasing in the interval.

Our critical points are x = 3 and x = -6. So we have those following intervals:

(-\infty, -6), (-6,3), (3, \infty)

We select a point x in each interval, and calculate f^{\prime}(x).

So

-------------------------

(-\infty, -6)

f^{\prime}(-7) = (-7-3)^{2}(-7+6) = (100)(-1) = -100

f is decreasing in the interval (-\infty, -6)

---------------------------

(-6,3)

f^{\prime}(2) = (2-3)^{2}(2+6) = (1)(8) = 8

f is increasing in the interval (-6,3).

------------------------------

(3, \infty)

f^{\prime}(4) = (4-3)^{2}(4+6) = (1)(10) = 10

f is increasing in the interval (3,\infty).

(c) At what points, if any, does f assume local maximum and minima values. ( if there is no local maxima put mo local maxima) if there is no local minima put no local minima

At a critical point x, if the function goes from decreasing to increasing, it is a local minima. And if the function goes from increasing to decreasing, it is a local maxima.

So, for each critical point is this problem:

At x = -6, f goes from decreasing to increasing.

So x = -6, f assume a local minima value

At x = 3, f goes from increasing to increasing. So, there it is not a local maxima nor a local minima. So, there is no local maxima for this function.

4 0
3 years ago
I’m super confused can anyone solve this
Ronch [10]

Answer:

x=5°, angle A=50°

Step-by-step explanation:

8x+11x-5+90=180

19x=95

x=5°

-->A= 11x-5

= 11*5-5

=50°

4 0
2 years ago
Find the measure of the line segment indicated, assume that lines which appear tangent are tangent. (2 questions) PLS help with
Brilliant_brown [7]

Answer:

1

Step-by-step explanation:

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3 years ago
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