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zysi [14]
3 years ago
10

Plz help______________

Mathematics
2 answers:
Savatey [412]3 years ago
7 0

Answer:

a

Step-by-step explanation:

timurjin [86]3 years ago
3 0
C (No restaurant) (Don’t care about this)
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Find the quotient and reduce to lowest terms: ((x²-4)/(3x)) ÷ ((x-2)/(2x)).
DENIUS [597]

Answer:   2/3 * (× + 2 )

Step-by-step explanation:

((x²-4)/(3x)) ÷ ((x-2)/(2x)).          ⇒   [ ( ײ - 4 ) * 2x ] ÷ [ ( × - 2 ) *3x ]

Simplifying by x   [ 2 * ( ײ - 4 ) ] ÷ [ ( × - 2 ) *3 ] ⇒ (2/3)*{ [ ( x-2 )*(×+2)]÷ (×-2) }

Simplifying by ( ×+2)     2/3 * (× + 2 )

3 0
3 years ago
If angles are congruent, solve by setting expressions equal to each other.<br><br> True<br> False
Taya2010 [7]
Answer: True, angles that are congruent are equaled to each other
3 0
3 years ago
There are three power plants [X, Y, Z] that at any given time each one either generates electricity or idles. Event A is that pl
insens350 [35]

We're told that

P(A\cap B)=0.15

P(A\cup B)^C=0.06\implies P(A\cup B)=0.94

P(B\mid A)=P(B^C\mid A)=0.5

where the last fact is due to the law of total probability:

P(A)=P(A\cap B)+P(A\cap B^C)

\implies P(A)=P(B\mid A)P(A)+P(B^C\mid A)P(A)

\implies 1=P(B\mid A)+P(B^C\mid A)

so that B\mid A and B^C\mid A are complementary.

By definition of conditional probability, we have

P(B\mid A)=P(B^C\mid A)

\implies\dfrac{P(A\cap B)}{P(A)}=\dfrac{P(A\cap B^C)}{P(A)}

\implies P(A\cap B)=P(A\cap B^C)

We make use of the addition rule and complementary probabilities to rewrite this as

P(A\cap B)=P(A\cap B^C)

\implies P(A)+P(B)-P(A\cup B)=P(A)+P(B^C)-P(A\cup B^C)

\implies P(B)-[1-P(A\cup B)^C]=[1-P(B)]-P(A\cup B^C)

\implies2P(B)=2-[P(A\cup B)^C+P(A\cup B^C)]

\implies2P(B)=[1-P(A\cup B)^C]+[1-P(A\cup B^C)]

\implies2P(B)=P(A\cup B)+P(A\cup B^C)^C

\implies2P(B)=P(A\cup B)+P(A^C\cap B)\quad(*)

By the law of total probability,

P(B)=P(A\cap B)+P(A^C\cap B)

\implies P(A^C\cap B)=P(B)-P(A\cap B)

and substituting this into (*) gives

2P(B)=P(A\cup B)+[P(B)-P(A\cap B)]

\implies P(B)=P(A\cup B)-P(A\cap B)

\implies P(B)=0.94-0.15=\boxed{0.79}

8 0
3 years ago
A college job placement office collected data about students’ GPAs and the salaries they earned in their first jobs after gradua
frez [133]

Answer:

X is the GPA

Y is the Salary

Standard deviation of X is 0.4

Standard deviation of Y is 8500

E(X)=2.9

E(Y)=47200

We are given that The correlation between the two variables was r = 0.72

a)y = a+bx

b = \frac{\sum(x_i-\bar{x})(y_i-\bar{y})}{\sum(x_i-\bar{x})^2} = \frac{r \times \sqrt{var(X) \times Var(Y)}}{Var(X)} =  \frac{0.72 \times \sqrt{0.4^2 \times 8500^2}}{0.4^2} = 15300

a=y-bx = 47200-(15300 \times 29) = 2830

So, slope =  15300

Intercept =  2830

So, equation : y = 2830+15300x

b) Your brother just graduated from that college with a GPA of 3.30. He tells you that based on this model the residual for his pay is -$1880. What salary is he earning?

y = 2830+15300 \times 3.3 = 53320

Observed salary = Residual + predicted = -1860+53320 = 51440

c)) What proportion of the variation in salaries is explained by variation in GPA?

The proportion of the variation in salaries is explained by variation in GPA = r^2 = (0.72)^2 =0.5184

8 0
3 years ago
The question is in the image! Please answer quickly.
Jobisdone [24]

Answer:

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5 0
2 years ago
Read 2 more answers
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