Answer:
Apparently 0 is the answer which makes sense
Explanation:
https://www.tiger-algebra.com/drill/(x-5)(x_1)/3(x_1)=x-5/3/
Answer:
0.0177
Explanation:
Cystic fibrosis is an autosomal recessive disease, thereby an individual must have both copies of the CFTR mutant alleles to have this disease. The Hardy-Weinberg equilibrium states that p² + 2pq + q² = 1, where p² represents the frequency of the homo-zygous dominant genotype (normal phenotype), q² represents the frequency of the homo-zygous recessive genotype (cystic fibrosis phenotype), and 2pq represents the frequency of the heterozygous genotype (individuals that carry one copy of the CFTR mutant allele). Moreover, under Hardy-Weinberg equilibrium, the sum of the dominant 'p' allele frequency and the recessive 'q' allele frequency is equal to 1. In this case, we can observe that the frequency of the homo-zygous recessive condition for cystic fibrosis (q²) is 1/3200. In consequence, the frequency of the recessive allele for cystic fibrosis can be calculated as follows:
1/3200 = q² (have two CFTR mutant alleles) >>
q = √ (1/3200) = 1/56.57 >>
- Frequency of the CFTR allele q = 1/56.57 = 0.0177
- Frequency of the dominant 'normal' allele p = 1 - q = 1 - 0.0177 = 0.9823
Answer: Mutualism
Explanation: The relationship between the crab and the sea anemone describes mutualism, a type of symbiotic relationship.
Mutualism describes the ecological interaction between two or more species that benefits both; typically involving the exchange of substances or services between both.
It plays a key role in ecology and is thought to have driven the evolution of much of the diversity currently in existence today.
The digestive system breaks down food, the respiratory system takes in oxygen, and the cardiovascular system delivers the oxygen and food to the cells.
