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77julia77 [94]
3 years ago
9

Find m/P A.30 B.80 C.150 D.330

Mathematics
2 answers:
Pavlova-9 [17]3 years ago
6 0
A =30 is the answer accordibg to tge scalar triangle
7nadin3 [17]3 years ago
4 0
 the answer is A. I think
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A yardstick casts a shadow of 24 in. at the same time a telephone pole casts a shadow of 20 ft 8 in. What is the height of the t
BabaBlast [244]
1 yd = 36 in;  20 ft 8 in = 248 in;
We will use a proportion:
36  : 24 = x : 248
24 x = 36 * 248
24 x = 8,928
x = 8,928 : 24 = 372
Answer:  C ) 372 in
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3 years ago
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photoshop1234 [79]
It would first be 0.7 and then 1.1
4 0
3 years ago
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"3. When we have two sorted lists of numbers in non-descending order, and we need to merge them into one sorted list, we can sim
iren [92.7K]

Answer:

Since we extract n elements in total, the algorithm for the running time for K sorted list is O (n log k+ k) = O (n log k)

Step-by-step explanation:

To understand better how we arrived at the aforementioned algorithm, we take it step by step

a, Construct a min-heap of the minimum elements from each of "k" lists.

The creation of this min-heap will cost O (k) time.

b) Next we run delete Minimum and move the minimum element to the output array.

Each extraction takes O (log k) time.

c) Then insert into the heap the next element from the list from which the element was extracted.

Now, we note that  since we extract n elements in total, the running time is

O (n log k+ k) = O (n log k).

So we can conclude that :

Since we extract n elements in total, the algorithm for the running time for K sorted list is O (n log k+ k) = O (n log k)

5 0
3 years ago
Help please!!!!!!!!!!!
kvasek [131]

Answer:

B. 2/3

Step-by-step explanation:

To solve this we have to take into account this axioms:

- The total probability is always equal to 1.

- The probability of a randomly selected point being inside the circle is equal to one minus the probability of being outside the circle.

Then, if the probabilities are proportional to the area, we have 1/3 probability of selecting a point inside a circle and (1-1/3)=2/3 probability of selecting a point that is outside the circle.

Then, the probabilty that a random selected point inside the square (the total probability space) and outside the circle is 2/3.

3 0
3 years ago
HELP ME I NEED HELP NOW I WILL GIVE CREDIT TO PEOPLE WHO ANSWER
kap26 [50]

Answer:

c

Step-by-step explanation:

3 0
2 years ago
Read 2 more answers
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