All categories

2 years ago

Simplify the expression 9t^2+14-17t+6t-8t^2

Mathematics

1 answer:

slamgirl [31]2 years ago

6 0

Answer:

t^2 - 11t + 14

Step-by-step explanation:

Begin by grouping like terms in 9t^2+14-17t+6t-8t^2.

First we have 9t^2 - 8t^2, or 1t^2.

Next, we have -17t + 6t, or -11t.

Last, we have the constant term 14.

The expression in simplified form is t^2 - 11t + 14.

You might be interested in

John walked x km. Sue has 3/7 walked less. Write an

maxonik [38]

Answer:

x - 3/7

Step-by-step explanation:

4 0

2 years ago

6ft and 10ft =? it's the pythagorean theorem

anyanavicka [17]

Answer:

11.7

Step-by-step explanation:

pythagorean theorem is $A^{2} +B^{2}=C^{2}$

apply that same formula soo $6^{2} +10^{2}=136^{2}$

then sqaure root 136 $\sqrt{136} =11.66190379$

round that soo now the answer is 11.7

7 0

2 years ago

Read 2 more answers

The fish population of Lake Collins is decreasing at a rate of 5% per year. In 2004 there were about 1,350 fish. Write an expone

ad-work [718]

Answer:

Part 1) The exponential function is equal to $y=1,350(0.95)^{x}$

Part 2) The population in 2010 was $992\ fish$

Step-by-step explanation:

Part 1) Write an exponential decay function that models this situation

we know that

In this problem we have a exponential function of the form

$y=a(b)^{x}$

where

y ----> the fish population of Lake Collins since 2004

x ----> the time in years

a is the initial value

b is the base

we have

$a=1,350\ fish$

$b=(100\%-5\%)=95\%=0.95$

substitute

$y=1,350(0.95)^{x}$ ----> exponential function that represent this scenario

Part 2) Find the population in 2010

we have

$y=1,350(0.95)^{x}$

For $x=(2010-2004)=6\ years$

substitute

$y=1,350(0.95)^{6}=992\ fish$

7 0

2 years ago

Can you help me please?

Artist 52 [7]

Answer:

Step-by-step explanation:

3 0

2 years ago

Read 2 more answers

The sum of the first 150 negative integers is represented using the expression What is the sum of the first 150 negative integer

Kamila [148]

Answer:

C. -11,325

Step-by-step explanation:

To know the answer, is convenient to replace some values of "n" in the sum $\sum_{(n=1)}^{150}[-1-(n-1)]$ .

The result would appear after adding up every value of the expression $\sum_{(n=1)}^{150}[-1-(n-1)]$ when n=1,2,3.....,150.
When n=1, the expression takes the value of (-1): $[-1-(1-1)]= (-1)-0=-1$ .
When n=2, the expression takes the value of (-2): $[-1-(2-1)]=-1-1=-2$ .
Following this way, for every n, we will obtain -n, then, the sum will be: $-1-2-3-4-5-6-...-150$ . This sum can actually be expressed as $\sum_{n=1}^{150}(-n)$ , which is the result of solving the initial expression of the sum $-1-(n-1)=-1-n+1=-n$ .
Finally, the sum of n=-1 to n=-150 equals -11,325.

7 0

3 years ago

Read 2 more answers