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Gwar [14]
3 years ago
7

A study shows that 70 out of 200 college students read the newspaper. Marysville College has 12,600 students.

Mathematics
2 answers:
Gnoma [55]3 years ago
8 0
4,410 is the answer I believe
Lubov Fominskaja [6]3 years ago
5 0
Your answer would be 4,410
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Rafael and his sister bought snacks for movie night.
Arada [10]

Answer:

1. $2.33

2. $2.99

Step-by-step explanation:

$6.99/3  

$5.98/2

4 0
3 years ago
Read 2 more answers
At the gym Merl swims every 6 days, runs every 4 days and cycles every 16 days. If she did all 3 activities today in how many da
garri49 [273]

Answer:

48 days

Step-by-step explanation:

Swim = every 6 days

Run = every 4 days

Cycles = every 16 days

Find the lowest common multiple of 6, 4 and 16

6 = 6, 12, 18, 24, 30, 36, 42, and 48

4 = 4, 8, 12, 16, 20, 24, 28, 32, 36, 40, 44, 48

16 = 16, 16, 32, 48, 64, 80, 96, 112, 128, 144, 160

The LCM of 6, 4 and 16 is 48

Therefore,

If she did all 3 activities today, she will do all 3 activities again in the next 48 days

8 0
2 years ago
Please solve and show how. I get a different answer each time. <br><br> -3(8 - x)
user100 [1]
Multiply -3 to both numbers

-3 multiplied by 8 is equal to - 24
-3 multiplied by -x is 3x (should be positive for double negative)

answer: 3x-24
8 0
3 years ago
If the Volume of a rectangular prism is 720 what is the width
Bess [88]

Answer:

The width of the rectangular prism is 9 cm.

Step-by-step explanation:

From the formula of the volume of a bar V=whl we see that w=\frac{V}{hl}=\frac{720}{8\cdot 10} = 9 cm.

7 0
2 years ago
Prove: cot(x) sec^4(x) = cot(x) +2tan(x) + tan^3(x)
masha68 [24]
\bf cot(\theta)=\cfrac{cos(\theta)}{sin(\theta)}&#10;\qquad\qquad &#10;sec(\theta)=\cfrac{1}{cos(\theta)}\quad\qquad  1+tan^2(\theta)=sec^2(\theta)\\\\\\&#10;tan(\theta)=\cfrac{sin(\theta)}{cos(\theta)}&#10;\qquad \qquad cot(\theta)=\cfrac{cos(\theta)}{sin(\theta)}&#10;\\\\&#10;-------------------------------\\\\&#10;cot(x)sec^4(x)=cot(x)+2tan(x)+tan^3(x)\\\\&#10;-------------------------------\\\\

\bf \textit{so, let's do the left-hand-side}\\\\&#10;cot(x)sec^2(x)sec^2(x)\implies cot(x)[1+tan^2(x)][1+tan^2(x)]&#10;\\\\\\&#10;cot(x)[1^2+2tan^2(x)+tan^4(x)]&#10;\\\\\\&#10;cot(x)+2tan^2(x)cot(x)+tan^4(x)cot(x)&#10;\\\\\\&#10;cot(x)+2\cdot \cfrac{sin^2(x)}{cos^2(x)}\cdot \cfrac{cos(x)}{sin(x)}+\cfrac{sin^4(x)}{cos^4(x)}\cdot \cfrac{cos(x)}{sin(x)}&#10;\\\\\\&#10;cot(x)+2\cdot \cfrac{sin(x)}{cos(x)}+\cfrac{sin^3(x)}{cos^3(x)}\implies \boxed{cot(x)+2tan(x)+tan^3(x)}
8 0
2 years ago
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