$\log a=7\hspace{15px} \log b=10\hspace{15px} \log c=3\\\\ \log \dfrac{a^8c^2}{b^3}=8\log{a}+2\log{c}-3\log{b}=(8)(7)+(2)(3)-(3)(10)\\\\=56+6-30=\boxed{32}$

The applicable rules of logarithms are ...

log(ab/c) = log(a) +log(b) -log(c)

log(a^b) = b·log(a)

6 0

3 years ago

I need some help with geometry?

kramer

39=9x+7-3x+20

Subtract 27 from each side

12=6x
2=x

Now plug in 2 for x to find AB and BC

9x+7= AB
9(2)+7=AB
18+7= AB
25= AB

-3x+20= BC
-3(2)+20= BC
-6+20= BC
14= BC

3 0

3 years ago

Browns department store is having a 1/4 off sale. How much would a shirt that regularly sells for 36.00 cost during the sale?

nadya68 [22]

Since the shirt is 25 percent off your paying for 75 percent of the shirt. 0.75(36) is 27. The shirt will cost 27.00

4 0

3 years ago

47 in = ? ft ? in 3 ft 11 in 4 ft 0 in 3 ft 9 in 564 ft 0 in

Veseljchak [2.6K]

Answer:

3ft 11 in

Step-by-step explanation:

1 foot equals 12 inches, 12 × 3 = 36 = 3 feet + 11 inches = 47 inches = 3ft 11in

8 0

2 years ago