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Harman [31]
3 years ago
14

A) You want to buy a new sweatshirt. They normally cost 28.80, but you found one that's on sale for 40% off its normal price. Ho

w much will you pay, not including tax?
1) $16.18


2) $17.28


3) $18.38


4) $19.48

b) If you get 17 out of 20 questions correct on this test, what percentage will you get correct?

1) 100%

2) 95%

3) 90%

4) 85%
Mathematics
1 answer:
arlik [135]3 years ago
7 0
For question A, the answer is 2.  Since the sale sweatshirt if 40% LESS, this means that 60% of the original price still remains. 28.80 x .60 = 17.28

For question B, the answer if 4.  You can divide 17 by 20 getting .85
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A rowing team rowed 90 miles while going with the current in the same amount of time as it took to row 10 miles going against th
pishuonlain [190]

Answer:

The speed in still water is 5 miles per hour.

Step-by-step explanation:

distance with current = 90 miles

distance against current = 10 miles

speed in still water = s

speed of current = 4 mph

speed with current = s + 4

speed against current = s - 4

time = t

speed = distance/time

distance = speed * time

With current:

90 = (s + 4) * t

Against the current:

10 = (s - 4) * t

We have a system of equations:

90 = (s + 4) * t

10 = (s - 4) * t

90 = ts + 4t

10 = ts - 4t

Subtract the second equation from the first equation.

80 = 8t

10 = t

t = 10

10 = t(s - 4)

10 = 10(s - 4)

1 = s - 4

s = 5

Answer: The speed in still water is 5 miles per hour.

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3 years ago
What is the missing term in the quadratic expression below?<br><br> (2x-3)(x-4)=2x^2+____ -12
cupoosta [38]

Answer:

ok

Step-by-step explanation:

6 0
3 years ago
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How do you find the area of a cube measuring 3ft it has 7sides
RUDIKE [14]
3 times 7= 21 times three =63

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3 years ago
Consider a tank used in certain hydrodynamic experiments. After one experiment the tank contains liters of a dye solution with a
Alja [10]

Answer:

t = 460.52 min

Step-by-step explanation:

Here is the complete question

Consider a tank used in certain hydrodynamic experiments. After one experiment the tank contains 200 liters of a dye solution with a concentration of 1 g/liter. To prepare for the next experiment, the tank is to be rinsed with fresh water flowing in at a rate of 2 liters/min, the well-stirred solution flowing out at the same rate.Find the time that will elapse before the concentration of dye in the tank reaches 1% of its original value.

Solution

Let Q(t) represent the amount of dye at any time t. Q' represent the net rate of change of amount of dye in the tank. Q' = inflow - outflow.

inflow = 0 (since the incoming water contains no dye)

outflow = concentration × rate of water inflow

Concentration = Quantity/volume = Q/200

outflow = concentration × rate of water inflow = Q/200 g/liter × 2 liters/min = Q/100 g/min.

So, Q' = inflow - outflow = 0 - Q/100

Q' = -Q/100 This is our differential equation. We solve it as follows

Q'/Q = -1/100

∫Q'/Q = ∫-1/100

㏑Q  = -t/100 + c

Q(t) = e^{(-t/100 + c)} = e^{(-t/100)}e^{c}  = Ae^{(-t/100)}\\Q(t) = Ae^{(-t/100)}

when t = 0, Q = 200 L × 1 g/L = 200 g

Q(0) = 200 = Ae^{(-0/100)} = Ae^{(0)} = A\\A = 200.\\So, Q(t) = 200e^{(-t/100)}

We are to find t when Q = 1% of its original value. 1% of 200 g = 0.01 × 200 = 2

2 = 200e^{(-t/100)}\\\frac{2}{200} =  e^{(-t/100)}

㏑0.01 = -t/100

t = -100㏑0.01

t = 460.52 min

6 0
3 years ago
find the common difference of the arithmetic sequence. 9, 13, 17, 21, . . . a. nine thirteenths b. 4 c. one and four ninths d. 2
shusha [124]
The answer is letter b.4
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3 years ago
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