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4 years ago

A body is accelerated continuously. What is the form of the graph?

Mathematics

2 answers:

never [62]4 years ago

8 0

If the body is accelerating then the graph would probably display a line going higher.

stepan [7]4 years ago

5 0

the answer for plato users is letter D!!

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Plz help :{<br><br> no bad answers plz!!!

topjm [15]

It is not periodic. A periodic dataset is a dataset that repeats the same pattern over time.

7 0

3 years ago

What is multiplicity

irga5000 [103]

Multiplicity means a large number. or large variety

3 0

3 years ago

A parabola can be drawn given a focus of

Volgvan

Answer:

$y=-\frac{1}{4}(x-2)^{2}+9$

Step-by-step explanation:

Any point on a given parabola is equidistant from focus and directrix.

Given:

Focus of the parabola is at $(2,8)$ .

Directrix of the parabola is $y=10$ .

Let $(x,y)$ be any point on the parabola. Then, from the definition of a parabola,

Distance of $(x,y)$ from focus = Distance of $(x,y)$ from directrix.

Therefore,

$\sqrt{(x-2)^{2}+(y-8)^{2}}=|y-10|$

Squaring both sides, we get

$(x-2)^{2}+(y-8)^{2}=(y-10)^{2}\\(x-2)^{2}=(y-10)^{2}-(y-8)^{2}\\(x-2)^{2}=(y-10+y-8)(y-10-(y-8))...............[\because a^{2}-b^{2}=(a+b)(a-b)]\\(x-2)^{2}=(2y-18)(y-10-y+8)\\(x-2)^{2}=2(y-9)(-2)\\(x-2)^{2}=-4(y-9)\\y-9=-\frac{1}{4}(x-2)^{2}\\y=-\frac{1}{4}(x-2)^{2}+9$

Hence, the equation of the parabola is $y=-\frac{1}{4}(x-2)^{2}+9$ .

4 0

3 years ago

Which of the following best describes segment AB in the figure below?

KengaRu [80]

Answer:

c i think.point. plus i really need the points

8 0

3 years ago

Use synthetic division to evaluate p(x)=6x^3-12x-8 for x=3

Harlamova29_29 [7]

Answer:

yeet on them

Step-by-step explanation:

4 0

3 years ago