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2 years ago

Someone plz help! Photo Above

Mathematics

1 answer:

TiliK225 [7]2 years ago

4 0

Answer:

-704

Step-by-step explanation:

Given the sequence

A = -4 - 6i

To find

Sum of terms from i=5 to i=15

<h3>Solution</h3>

We see the sequence is AP

The required sum is

S₅₋₁₅ = S₁₅ - S₄

Using sum of AP formula

Sₙ = 1/2n(i₁ + iₙ)

Finding the required terms

i₁ = - 4- 6 = -10
i₄ = -4 -6*4 = - 28
i₁₅ = -4 -6*15 = -94

Getting the sum

S₄ = 1/2*4*(-10 - 28) = -76
S₁₅ = 1/2*15*(-10 - 94) = -780
S₅₋₁₅ = S₁₅ - S₄ = -780 - (-76) = - 704

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204 hours

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Step-by-step explanation:

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2 years ago

Solve for x and y matrix

charle [14.2K]

Answer:

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Step-by-step explanation:

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2 years ago

Please I need help with this!!!!!!!

inysia [295]

Answer:

Step-by-step explanation:

1). Step 4:

$x=5^{\frac{4}{3}}=(5^4)^{\frac{1}{3}}$

$x=\sqrt[3]{5^4}$ [Since, $a^{\frac{1}{3}}=\sqrt[3]{a}$ ]

$x=\sqrt[3]{5\times 5\times 5\times 5}$

Step 5:

$x=\sqrt[3]{(5)^3\times 5}$

$x=\sqrt[3]{5^3}\times \sqrt[3]{5}$

2). He simplified the expression by removing exponents from the given expression.

3). Let the radical equation is,

$(3x-1)^{\frac{1}{5}}=2$

Step 1:

$(3x-1)^{\frac{1}{5}\times \frac{5}{1} }=2^{\frac{5}{1}}$

Step 2:

$(3x-1)=2^5$

Step 3:

$3x=32+1$

Step 4:

$x=11$

4). By substituting $x=11$ in the original equation.

$(3\times 11-1)^{\frac{1}{5}}=(32)^\frac{1}{5}$

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$=2$

There is no extraneous solution.

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2 years ago

The miller wants to bake a loaf of bread,but he didnt have any flour. He decided to grind just enough for eight loaves. If it ta

anyanavicka [17]

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3 years ago