An absolute value inequality that represents the weight of a 5-foot male who would not meet the minimum or maximum weight requirement allowed to enlist in the Army is 97 lbs < x < 132 lbs.
<h3>What are inequalities?</h3>
Inequalities help us to compare two unequal expressions. Also, it helps us to compare the non-equal expressions so that an equation can be formed.
It is mostly denoted by the symbol <, >, ≤, and ≥.
The median weight for a 5 foot tall male to enlist in the US Army is 114.5 lbs. This weight can vary by 17.5 lbs. Therefore, the inequality can be written as,
(114.5 - 17.5) lbs < x < (114.5 + 17.5) lbs
97 lbs < x < 132 lbs
Hence, an absolute value inequality that represents the weight of a 5-foot male who would not meet the minimum or maximum weight requirement allowed to enlist in the Army is 97 lbs < x < 132 lbs.
Learn more about Inequality:
brainly.com/question/19491153
#SPJ1
‾‾‾‾√140≈11.832159566199232
Answer:
$110
Step-by-step explanation:
So first you have to do 15*4. We get the 4 from the admission fees and the 15 from the number of dances they attend. From this answer we can see the total of money they will be paying for admission for the 15 dances.
15*4=$60
However, our answer isn't just $50 as we are also told membership costs $50. So no we add $50 to $60, which gives us an answer of $110, which is the amount the member will pay if they attend 15 dances during the school year.
3/4 (x-12)=12
3/4x - 9= 12
+9 +9
3/4x=21
*3/4 *3/4
x= 15 3/4
and
3/4y-12=12
+12 +12
3/4y = 24
*3/4 *3/4
y= 18
So I think maybe the example for the first problem created some confusion, and you may want to have your child take another look.
If we numbered the top half 1 to 9 going from left to right, numbers 1, 2, 6, 7 and 8 are right. They worked because the top number (numerator) perfectly fit into the bottom number (denominator). This is not true for the rest.
The key is to find the largest number that you can think of that will go into BOTH the top and the bottom evenly.
So for number 3: 18/24; 18 does not fit evenly into 24. The highest number that will fit into both is 6, so you divide both top and bottom by 6 and your answer is 3/4.
Number 4: 45/54; the highest number that goes into both is 9, so you divide both top and bottom by 9 and your answer is 5/6.
Number 5: 55/66; the highest number that can go into both is 11, so the answer is 5/6.
Is this making sense?
The bottom, numbering 1 to 9 from left to right. The correct ones are 1, 6 and 9.
For 2: 14/41 is about 15/40. Both can be divided by 5, so the answer is 3/8.
For 3: 20/81 is about 20/80, and 2/8 is close, but can still be divided by 2, so the answer is 1/4.
For 4: 24/49 is closer to 25/50 than 20/50. 25/50 can be divided by 25, so the answer is 1/2.
For 5: it was all correct, but the answer can be further reduced from 2/8 to 1/4.
For 7: 23/72 is about 25/75, and 25 goes into both, so it reduces to 1/3.
For 8: 13/21 is about 15/20, and 5 goes into both, so the answer is 3/4.
As your child continues to learn this, remember that if he or she gets an answer like 2/6 or 6/12, they should ask themselves if they can further reduce the fractions- 2/6 reduces to 1/3, and 6/12reduces to 1/2. I know it's confusing, but they do get the hang of it with practice
