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3 years ago

What is the range of the function y=(x+2)(x-4) Please explain how you got it as well

2 answers:

6 0

Lets simplify the function into it's correct quadratic form first, just by multiplying the parenthesis.

Y = x^2 -2x -8

Now we know that the range is from the minimum y-value to the maximum (if there is one)

In functions like this, they have the form y = ax^2 + bx + c, where c is the minimum or maximum for the given function

In this case, it's a minimum because there aren't any y points on the graph smaller than -8

That means the range is: y >= -8

Dima020 [189]3 years ago

4 0

Answer:

The range is between -2 and +4.

Step-by-step explanation:

To find range you just need to get X ignoring the Y.

(X+2) is X= -2

(X-4) is X = +4

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How can 8 ounces be expressed in pounds

vichka [17]

The answer would be .5 pounds

1 ounce is equal to .0625 lbs

so 8 * .0625 = .5

hope this helps :)

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3 years ago

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How can I work this out or solve this?

timurjin [86]

Simple, just add the values of the school distance with the library distance, then substract the distance to the park.

If you are lazy like me, the answer is C, 1.08.

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4 years ago

Can someone please help me?

salantis [7]

Answer:

Step-by-step explanation:

24*68*15

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3 years ago

I REALLY NEED HELP WHY WONT ANYONE HELP ME, I POSTED THIS SO MANY TIMES. PLEASE IT’S NOT HARD, I JUST DO NOT UNDERSTAND. PLEASE

atroni [7]

Answer:

I was unclear if you needed this solved in vertex or standard form, so I gave you both.

Vertex form: $(x - 4)^2 - 1$

Standard form: $x^2 - 8x + 15$

Step-by-step explanation:

This is a quadratic equation. In order to solve this problem, you will need these equations:

Vertex form: $a(x - h)^2 + k$

Standard form: $ax^2 + bx + c$

Starting with vertex form:

The vertex is (4, -1). When putting this into your equation, substitute the "x" value for h, and substitute the "y" value for k.

$a(x - 4)^2 - 1$

You can disregard the "a" for this particular problem because it is equal to 1.

Standard form:

Now that you have vertex form, you can expand it into standard form.

$(x-4)^2 - 1$

Use the FOIL method to multiply (x - 4)(x - 4).

This will equal $x^2 - 8x + 16$ .

Keep in mind that you still have a -1 from your original equation to take into account. Once you subtract 1, this will leave you with:

$x^2 - 8x + 15$

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3 years ago

Frankie wants to build a path from one corner of his yard to the opposite corner. His yard measures 20 ft. x 32 ft. What will be

riadik2000 [5.3K]

Frankie's yard is a rectangle with the longer side = 32ft and the shorter side = 20ft. You want to find the length of the diagonal going through the rectangle. In essence, you basically have a triangle with two sides, one 32ft, the other 20ft, and you're looking for the hypotenuse.

Let's call a=32, b=20, and you're looking for the hypotenuse c. Use the Pythagorean theorem:
${a}^{2} + {b}^{2} = {c}^{2}$
Plug the numbers in to find c, the length of your path! So
$\sqrt{{32}^{2} + {20}^{2}} = 37.7$

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3 years ago

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