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den301095 [7]
2 years ago
13

Fill in the table using this function rule:

Mathematics
2 answers:
erik [133]2 years ago
6 0
The function:
y=-3x+4

For x=-4:
y=-3*(-4)+4=12+4=16

For x=-2:
y=-3*(-2)+4=6+4=10

For x=-4:
y=-3*(0)+4=0+4=4

For x=-4:
y=-3*(2)+4=-6+4=-2

The solution:
 x | y
-4 | 16
-2 | 10
 0 |  4
 2 | -2
patriot [66]2 years ago
3 0
When x is -4: 
y=-3(-4)+4 
y=16 
-2: 
y=-3(-2)+4 
y=-2 
0: 
y=-3(0)+4 
y=4
2: 
y=-3x2+4 
-2 

Hope that helps 
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nadezda [96]
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3 0
2 years ago
Diamonds have a density of 3.5 LaTeX: \frac{g}{cm^3}g c m 3. How big is a diamond that has a mass of 0.10 g?
liubo4ka [24]

For this case we have that by definition, the density is given by:

d = \frac {M} {V}

Where:

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V: It is the volume of the diamond

According to the data of the statement we have:

d = 3.5 \frac {g} {cm ^ 3}\\M = 0.10 \ g

So the volume is:

V = \frac {M} {d}\\V = \frac {0.10 \ g} {3.5 \frac {g} {cm ^ 3}}\\V = 0.02857\\V = 0.03 \ cm^3

Thus, the volume of the diamond is approximately 0.03 \ cm ^ 3

Answer:

0.03 \ cm ^ 3

3 0
3 years ago
-1/5(x-4)=-2 how do you solve this equation
m_a_m_a [10]
Multiple both sides by 5/1 and get

-1/1 • (x-4) = -10/1

divide the numbers and get

-1 • (x-4) = -10

remove the parentheses

- x-4 = 10

move the constant to the right

-x = -10-4

calculate

-x = -14

change the signs

x= 14
8 0
2 years ago
Find the area of this figure. Brainliest to first correct answer. Tysm
larisa [96]
Area of Triangle:
A = 1/2 bh = 1/2 (5)(12) = 30 m^2

Area of semicircle:
A = 1/2 π r^2 = 1/2 π 6^2 = 18<span>π m^2

Area of figure = </span>Area of semicircle + Area of Triangle 
Area of figure = 18π  + 30 m^2

Answer is C.
18π  + 30 m^2
5 0
3 years ago
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Neporo4naja [7]

Im think its C. Accounting.

Hope that is correct.

7 0
2 years ago
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