Answer:
D) p³ + 2; when p = 3 the number of plants is 29.
Step-by-step explanation:
Illiana cubed (³) the number of original plants, p, in the garden. Then, she added 2 more plants. We will use n for the number of total plants.
So, the equation should be p³ + 2. Substitute our value for p into the equation and solve.
p³ + 2 = n
3³ + 2 = n
27 + 2 = n
29 = n
There are 29 total plants.
The answer, then, is the last option, p³ + 2; when p = 3 the number of plants is 29.
Good luck ^^
<h2>
Answer:</h2>
The value of x is -1/2
<h2>
Step-by-step explanation:</h2><h3>Question :</h3>
Solve the equation of f(x + 2) = f(x - 2) + 4, where f(x) = 3 + 2x + x^2
<h3>Solution :</h3>
First, we need to split the equation and find the answer to each function
f(x + 2) = 3 + 2(x + 2) + (x + 2)^2
f(x + 2) = 3 + 2x + 4 + x^2 + 4x + 4
<u>f(x + 2) = x^2 + 6x + 11</u>
f(x - 2) = 3 + 2(x - 2) + (x - 2)^2
f(x - 2) = 3 + 2x - 4 + x^2 - 4x + 4
<u>f(x - 2) = x^2 - 2x + 3</u>
Second, we need to find the value of x
f(x + 2) = f(x - 2) + 4
=> x^2 + 6x + 11 = x^2 - 2x + 3 + 4
=> x^2 - x^2 + 6x + 11 = - 2x + 3 + 4
=> 6x + 11 = -2x + 7
=> 6x = -2x - 4
=> 6x + 2x = -4
=> 8x = -4
=> x = -1/2
<h3>Conclusion :</h3>
The value of x is -1/2
Answer:
C. -4a + 22b
Step-by-step explanation:
12a + 26b -4b – 16a
= 12a – 16a + 26b – 4b
= -4a + 22b
Answer:
$-107
Step-by-step explanation:
From the problem we know the probability of randomly selecting a person alive throughout the year: 0.9989
Now, the probability that a person does NOT live would be the complement, that is:
1 - 0.9989 = 0.0011
Now to know the real value of the policy, we must first subtract what he paid for it, that is:
80000 - 195 = $ 79805
Now, to know what the value waiting for that person would be the subtraction of the real value that will be gained by the probability of not living, less what the policy payment for the probability of surviving, thus:
0.0011 * 79805 - 0.9989 * 195 = -107
Which means this man is actually losing $ 107
It would be the second table because is the only one with 10 small green apples and 12 large red apples that add up.
