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Degger [83]
3 years ago
7

Combine terms: 12a + 26b -4b – 16a.

Mathematics
2 answers:
Liula [17]3 years ago
5 0

Answer:

C. -4a + 22b

Step-by-step explanation:

12a + 26b -4b – 16a

= 12a – 16a + 26b – 4b

= -4a + 22b

Mice21 [21]3 years ago
3 0

Answer:

(a)

Step-by-step explanation:

collect the available like terms.

16a -12a +26b-4b

4a+22b

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What is 433.38 in word form
Umnica [9.8K]

Answer:

Four hundred Thirty-three and thirty-eight hundredths

Step-by-step explanation:

the four is four hundred

the two three's after the four are thirty-three

and the three and eight after the decimal are thirty-eight hundredths


4 0
3 years ago
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A square patio has an area of 215 square feet. How long is each side of the patio to the nearest 0.05
lara31 [8.8K]
Since a square has four sides you divide 215 by 4 your answer will be 53.75 Each side 53.75 long
4 0
3 years ago
pls help me with this i’ve been stuck on it for a while but i did it on paper and it doesn’t look right
inn [45]

i will fill the boxes from top down

4(-2)-5=-13

4(1)-5=-1

4(2)-5=3

4(3)-5=7

5 0
3 years ago
Does the set {t, t Int} form a fundamental set of solutions for t^2y" -- ty' +y = 0?
Ivanshal [37]

Answer:

yes

Step-by-step explanation:

We are given that a Cauchy Euler's equation

t^2y''-ty'+y=0 where t is not equal to zero

We are given that two solutions of given Cauchy Euler's equation are t,t ln t

We have to find  the solutions are independent or dependent.

To find  the solutions are independent or dependent we use wronskain

w(x)=\begin{vmatrix}y_1&y_2\\y'_1&y'_2\end{vmatrix}

If wrosnkian is not equal to zero then solutions are dependent and if wronskian is zero then the set of solution is independent.

Let y_1=t,y_2=t ln t

y'_1=1,y'_2=lnt+1

w(x)=\begin{vmatrix}t&t lnt\\1&lnt+1\end{vmatrix}

w(x)=t(lnt+1)-tlnt=tlnt+t-tlnt=t where t is not equal to zero.

Hence,the wronskian  is not equal to zero .Therefore, the set of solutions is independent.

Hence, the set {t , tln t} form a fundamental set of solutions for given equation.

6 0
3 years ago
Triangle ABC has vertices A(4, 5), B(0, 5), and C(3, –1). The triangle is translated 3 units to the left and 1 unit up. What are
tankabanditka [31]

The coordinates of point B' are (-3, 6).

<h2>Given that</h2>

Triangle ABC has vertices A(4, 5), B(0, 5), and C(3, –1).

The triangle is translated as 3 units to the left and 1 unit up.

<h3>We have to determine</h3>

What are the coordinates of B' after the translation?

<h3>According to the question</h3>

Triangle ABC has vertices A(4, 5), B(0, 5), and C(3, –1).

The triangle is translated as 3 units to the left and 1 unit up.

To find the coordinates of B', we will shift the x-coordinate of point B to left by 3 units and the y-coordinate of point B to 1 unit up.

After the given transformation the coordinates of point B' would be:

\rm B(0, \ 5) = B (0-3, \ 5+1) = B(-3, \ 6)

Therefore, the coordinates of point B' are (-3, 6).

To know more about Transformation click the link given below.

brainly.com/question/26297555

6 0
3 years ago
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