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Shalnov [3]
3 years ago
6

Three students have already enrolled for a creative writing class. The teacher will cancel the class if there are fewer than 10

students enrolled. Write three values for numbers of students needed to sign up so that the the creative writing class can be held
Mathematics
1 answer:
JulijaS [17]3 years ago
7 0

Answer:

7, 10 and 15

Step-by-step explanation:

Given

S_1= 3  --- Students already enrolled

Total = 10\ (less)

Required

Determine the additional number of students needed for the teacher not to cancel the class

First, we need to calculate the number of students for the teacher to cancel the class.

Represent this with x.

So, we have:

S_1 + x < Total

Make x the subject

x < Total - S_1

Substitute values for Total and S1

x < 10 - 3

x < 7

This means that if less than 7 additional students come to the class, the teacher will cancel the class.

So, for the teacher not to cancel the class, the students must be 7 or greater (i.e. 7, 8, 9, 10....)

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3 years ago
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Part A. Write an equation of a line that is perpendicular to the line y = 2/3x + 5 and passes through the point (4, 0).
fenix001 [56]

Answer:

y = -\frac{3}{2}x+6

Step-by-step explanation:

Given:

The given equation of the line y = \frac{2}{3} x + 5 that passes through the point (4, 0).

Part A.

The equation of the line.

y=mx+c-----------(1)

Where:

m = Slope of the line

c = y-intercept

The given equation of the line.

y = \frac{2}{3} x + 5

Comparing the given equation with equation 1.

The slope of the line is m=\frac{2}{3} and y-intercept c = 5

We know that the slope of the perpendicular line is (-\frac{1}{m}).

So the slope of the perpendicular line is (m=-\frac{1}{\frac{2}{3}}=-\frac{3}{2}).

Using point slope formula we write the equation of the perpendicular line that passes through the point (4, 0).

y-y_{1} = m(x-x_{1}

Now we substitute the slope of the perpendicular line m=-\frac{3}{2} and y_{1} = 0, x_{1}=4 from point (4, 0) in above equation.  

y-0 = -\frac{3}{2}(x-4)

y = -\frac{3}{2}x-(-\frac{3}{2}\times 4)

y = -\frac{3}{2}x-(-3\times 2)

y = -\frac{3}{2}x-(-6)

y = -\frac{3}{2}x+6

Therefore the perpendicular line equation is y = -\frac{3}{2}x+6.

Part B.

1. The slope of the perpendicular line is m=-\frac{3}{2}.

2. The y-intercept of the perpendicular line is 6.

3. The equation of the line y = -\frac{3}{2}x+6 is perpendicular to the equation of line y = \frac{2}{3} x + 5.

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3 years ago
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Answer:

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Answer:

b

Step-by-step

5x+3=6x-5

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4 years ago
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tigry1 [53]

Answer:

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Its easy if you plug it into the Desmos graphing calculator. Just do

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