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seraphim [82]
3 years ago
14

a rectangle has a length of 8m and a width of 4.5m. A parallelogram has a length of 6 m. The area of the parallelogram is twice

the area of the rectangle. What is the height of the parallelogram
Mathematics
1 answer:
Tcecarenko [31]3 years ago
6 0

Answer:

12m

Step-by-step explanation:

work out the area of the rectangle then times it by 2 because the parallelogram is twice the area of the rectangle. 8 × 4.5m = 36m². 36 ×2 = 72cm². Now you do 72 ÷ 6 = 12 . the answer is 12m.

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Novosadov [1.4K]

Answer:

(d)  y= (1 1/9)x

Step-by-step explanation:

A proportional relation is described by the equation ...

 y = kx

Dividing by x shows how to find the value of k:

 k = y/x

For the given values of y and x, the value of k is found to be ...

 k = (5/6)/(3/4) = (5/6)(4/3) = 20/18 = 10/9 = 1 1/9

The relationship is represented by the equation ...

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2 years ago
Natalie went to the shoe store and bought two pairs of sneakers. One pair was $35.60, and the other was $49.95. If she has $100.
Contact [7]

First you need to add the prices to get 85.55. Then 100 - 85.55 is 14.45.




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6 0
3 years ago
Read 2 more answers
Area of a triangle with points at (-9,5), (6,10), and (2,-10)
Ann [662]
First we are going to draw the triangle using the given coordinates. 
Next, we are going to use the distance formula to find the sides of our triangle.
Distance formula: d= \sqrt{(x_{2}-x_{1})^2+(y_{2}-y_{1})^2}

Distance from point A to point B:
d_{AB}= \sqrt{[6-(-9)]^2+(10-5)^2}
d_{AB}= \sqrt{(6+9)^2+(10-5)^2}
d_{AB}= \sqrt{(15)^2+(5)^2}
d_{AB}= \sqrt{225+25}
d_{AB}= \sqrt{250}
d_{AB}=15.81

Distance from point A to point C:
d_{AC}= \sqrt{[2-(-9)]^2+(-10-5)^2}
d_{AC}= \sqrt{(2+9)^2+(-10-5)^2}
d_{AC}= \sqrt{11^2+(-15)^2}
d_{AC}= \sqrt{121+225}
d_{AC}= \sqrt{346}
d_{AC}= 18.60

Distance from point B from point C
d_{BC}= \sqrt{(2-6)^2+(-10-10)^2}
d_{BC}= \sqrt{(-4)^2+(-20)^2}
d_{BC}= \sqrt{16+400}
d_{BC}= \sqrt{416}
d_{BC}=20.40

Now, we are going to find the semi-perimeter of our triangle using the semi-perimeter formula:
s= \frac{AB+AC+BC}{2}
s= \frac{15.81+18.60+20.40}{2}
s= \frac{54.81}{2}
s=27.41

Finally, to find the area of our triangle, we are going to use Heron's formula:
A= \sqrt{s(s-AB)(s-AC)(s-BC)}
A=\sqrt{27.41(27.41-15.81)(27.41-18.60)(27.41-20.40)}
A= \sqrt{27.41(11.6)(8.81)(7.01)}
A=140.13

We can conclude that the perimeter of our triangle is 140.13 square units.

3 0
2 years ago
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Write the equation of the lines in slope-intercept form (y=mx+b)

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P.S * represents multiplication
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